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3 years ago

S waves arrive at distant points before other seismic waves, true or false

Physics

1 answer:

Step2247 [10]3 years ago

3 0

False. p waves, than s waves

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A father is trying to teach his child to ice skate. As the child stands still, the father pushes him forward with an acceleratio

rjkz [21]

Hi there!

We can use Newton's Second Law:

$\Sigma F = ma$

∑F = net force (N)

m = mass (kg)

a = acceleration (m/s²)

We are given the mass and acceleration, so:

∑F = 20 · 2 = 40 N

4 0

2 years ago

Most interstellar clouds are: Most interstellar clouds are: much bigger than our solar system. similar in size to clouds in Eart

cupoosta [38]

Answer:

Most interstellar clouds are much bigger than our solar system.

Explanation:

An interstellar cloud refers:

It is generally an accumulation of gas, plasma, and dust in our and other galaxies.
It is basically a denser-than-average region of the interstellar medium (ISM).

Interstellar clouds can be large up to 106 solar masses

It is also often said to be the most massive entities in the galaxy.

Hence

we can say about Interstellar clouds,

They are much bigger than our solar system.

learn more about interstellar clouds here:

brainly.com/question/14726563

#SPJ4

4 0

1 year ago

Se o Universo tem uma idade definida, de aproximadamente 13,7 bilhões de anos, o que existiu antes do big-bang?

UkoKoshka [18]

Ninguém sabe exatamente

4 0

2 years ago

What do we mean by the event horizon of a black hole?

Fynjy0 [20]

The correct answer is: C. It is the point beyond which neither light nor anything else can escape.

6 0

3 years ago

Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml

Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of electric field

$E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}$

$E=2.41\times10^{3}\ V/m$

Hence, The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

3 0

3 years ago