Explanation:
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Answer:
0.36 A.
Explanation:
We'll begin by calculating the equivalent resistance between 35 Ω and 20 Ω resistor. This is illustrated below:
Resistor 1 (R₁) = 35 Ω
Resistor 2 (R₂) = 20 Ω
Equivalent Resistance (Rₑq) =?
Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:
Rₑq = (R₁ × R₂) / (R₁ + R₂)
Rₑq = (35 × 20) / (35 + 20)
Rₑq = 700 / 55
Rₑq = 12.73 Ω
Next, we shall determine the total resistance in the circuit. This can be obtained as follow:
Equivalent resistance between 35 Ω and 20 Ω (Rₑq) = 12.73 Ω
Resistor 3 (R₃) = 15 Ω
Total resistance (R) in the circuit =?
R = Rₑq + R₃ (they are in series connection)
R = 12.73 + 15
R = 27.73 Ω
Finally, we shall determine the current. This can be obtained as follow:
Total resistance (R) = 27.73 Ω
Voltage (V) = 10 V
Current (I) =?
V = IR
10 = I × 27.73
Divide both side by 27.73
I = 10 / 27.73
I = 0.36 A
Therefore, the current is 0.36 A.
An example of a negative incentive for producers is the
sharp increase in production costs. Producers are the one who manage the production
costs and even the production budget. Anything that relates the production
department is entitled to the management of production producers.
There is what we called positive and negative incentives and
both of these can affect consumers and producers. Positive incentives are those
situations which will give a certain outcome that will benefit the producers,
for example, during the peak season there will be a high demand of products, and
this gives the chance of producers to demand a higher price from the consumers,
in this situation, there will be a big chance of increase sales. A sharp increase in production costs is a
loss for the producers. If there will be
an increase in production costs, the budget will be greatly affective and even
though it is not a peak season, there’s a big chance also to increase prices
which we know, consumers are not fond of.
Answer:
Fluorine is the most reactive element
Answer:
Number of electrons, 
Explanation:
It is given that,
Resistance, R = 4 ohms
Current, I = 3 A
Time, t = 5 min = 300 s
We need to find the number of electrons pass through the resistor during this time interval. Let the number of electron is n.
i.e. q = n e ...............(1)
And current, 
e is the charge of an electron
So, the number of electrons pass through the resistor is 
. Hence, this is the required solution.
