Answer:
wavelength = 4 m
Explanation:
For distance 6 and 8m and speed of sound in air = c.
The travel time form the various distances 6 and 8 are 6/c and 8/c respectively.
cos(wt1) + cos(wt2) = 0
for a shift in phase t1 = t - 6/c,
t2 = t - 8/c
substituting t1 and t2
cos(π - w(t - 8/c)) = cos(w(t - 6/c))
solving using trigonometry identities in radians.
we have,
π - 2πn = w(t - 8/c) - w(t - 6/c)
putting w = 2πf
π - 2πn = 2πf(t - 8/c) - 2πf(t - 6/c)
dividing both sides by π
1 - 2n = 2ft - 16(f/c) - 2ft + 12(f/c)
simplifying we have,
1 - 2n = -4(f/c)
solving for f we have,
f = c/4(2n - 1)
putting n=1 and c = 343m/s
f = (343/4)*(2(1) - 1)
f = 85.75 Hertz
wave lenght = c/f , where c= speed of sound in air , f= frequency
wave lenght = 343/85.75 = 4m
<u>F = M A </u> (Newton's #2)
Force = (0.15 kg) (12 m/s²)
Force = (0.15 · 12) (kg·m/s²)
<em>Force = 1.8 Newtons</em>
B) The transfer of energy from the hydrosphere to the atmosphere
This is because oceans are part of the hydrosphere. As the air warms it flows up into the atmosphere.
Hope this helps!
Planck's equation states that
E = hf
where
E = the energy,
h = Planck's constant
f = the frequency
Because
c = fλ
where
c = velocity of light,
λ = wavelength
therefore
E = h(c/λ)
Photon #1:
The wavelength is λ₁ = 60 nm.
The energy is
E₁ = (hc)/λ₁
Photon #2:
The energy is twice that of photon #1, therefore its energy is
E₂ = 2E₁ = (hc)/λ₂.
Therefore

Answer: 30 nm