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2 years ago

What is the spring constant of a bungee cord that stretches an additional 1.2

Physics

2 answers:

ziro4ka [17]2 years ago

4 0

Answer:

Explanation:

rosijanka [135]2 years ago

4 0

Answer:

83.3 N/m

Explanation:

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5. The wire in consists of two segments of different diameters but made from the same metal. The current in segment 1 is I1. a.

Volgvan

Answer:

hello your question is incomplete attached below is the complete question

answer :

a) I1 = I2

b) J1 > J2

c) E 1 > E2

d) ( vd1 ) > ( vd2 )

Explanation:

a) The currents in the two segments are the same i.e. I1 = I2 and this is because the segments are connected in series

b) Comparing the current densities J1 and J2 in the two segments

note : current density ∝ 1 / area

The area of the second segment is > the area of first segment therefore

J1 > J2

J1 ( current density of first segment )

J2 ( current density of second segment )

c) Comparing the electric field strengths E1 and E2

note : electric field strength ∝ current density

since current density of first segment is > current density of second segment and conductivity of the materials are the same hence

E 1 > E2

d) Comparing the drift speeds Vd1 and Vd2

( vd1 ) > ( vd2 )

this because ; vd ∝ current density

7 0

3 years ago

Which is harder, air tight or water tight seals?

Vladimir [108]

Should be an air tight seal

4 0

3 years ago

The elements from this section of the periodic table all belong to the same

Lady_Fox [76]

Answer:

The answer is:

B) period

3 0

2 years ago

Observe the given figure and find the the gravitational force between m1 and m2.

Leno4ka [110]

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

$F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}$

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

$F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N$

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N

8 0

2 years ago

Evan drew a diagram to illustrate radiation.

Vesna [10]

The correct answer is:

D. Electromagnetic waves.

The arrows represent electromagnetic waves.

$|Huntrw6|$

8 0

2 years ago