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viktelen [127]
2 years ago
7

What is the spring constant of a bungee cord that stretches an additional 1.2

Physics
2 answers:
ziro4ka [17]2 years ago
4 0

Answer:

A

Explanation:

rosijanka [135]2 years ago
4 0

Answer:

83.3 N/m

Explanation:

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A

Explanation:

Name me brainliest plzzzzz

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The weight is not coming from the center of the mass because the force that act on it is not is equal is side.(2) section B donot have weight because the ruler bend down and section be raise up so no weight.
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2 years ago
You will be colliding two carts in this lab. Select all the systems for which you predict the total momentum of the system will
baherus [9]

From the momentum conservation we know that the initial momentum is equal to the final momentum. The momentum in a singular way can be defined as the product between the mass and the velocity of an object. In the presented system, however, there are two objects, therefore the mass of both and the speed of both, before and after the collision must be taken into account. Mathematically we could describe this as

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

Here,

m_{1,2} = Mass of each object

u_{1,2} = Initial velocity of each object

v_{1,2} = Final velocity of each object

From here we can realize that it is necessary to use the system on both cars to be able to predict what will happen either with their masses, or their speeds.

The correct answer is C.

6 0
3 years ago
Assume a rectangular strip of a material with an electron density of n=5.8x1020 cm-3. The strip is 8 mm wide and 0.8 mm thick an
vampirchik [111]

Answer: I = 111.69 pA

Explanation: The hall effect is all about the fact that when a semiconductor is placed perpendicularly to a magnetic field, a voltage is generated which could be measured at right angle to the current path. This voltage is known as the hall voltage.

The hall voltage of a semiconductor sensor is given below as

V = I×B/qnd

Where V = hall voltage = 1.5mV =1.5/1000=0.0015V

I = current =?,

n= concentration of charge (electron density) = 5.8×10^20cm^-3 = 5.8×10^20/(100)³ = 5.8×10^14 m^-3

q = magnitude of an electronic charge=1.609×10^-19c

B = strength of magnetic field = 5T

d = thickness of sensor = 0.8mm = 0.0008m

By slotting in the parameters, we have that

0.0015 = I × 5/5.8×10^14 × 1.609×10^-19×0.0008

0.0015 = I×5/7.446×10^-8

I = (0.0015 × 7.446×10^-8)/5

I = 111.69*10^(-12)

I = 111.69 pA

3 0
2 years ago
Yub87654d HELP there is this person trying to kid,.,nap,./, kids so if you see an account called Hernyana report there questions
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