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3 years ago

What characteristics of EM waves did you discover?

Physics

2 answers:

slega [8]3 years ago

7 0

Answer: reflection

Refraction

Energy

Speed

Explanation:

Reflection results when em wave hits a plane surface and returns in the same angle it incident

Refraction is the change in velocity and direction of em wave as it crosses boundaries of different medium

The energy of em wave is evenly distributed in electric field and magnetic field

The speed of em wave is the same as 3×10^8

jarptica [38.1K]3 years ago

4 0

The characteristics of electromagnetic waves typically represent as follows:

There are changes in the electric and magnetic fields simultaneously so that both fields have maximum and minimum values at the same time and place.
The direction of the electric field and the magnetic field are perpendicular to each other. The direction of both is perpendicular to the direction of the wave propagation.
The shape of electromagnetic waves is transverse waves.
It has general wave characteristics like polarization, reflection, refraction, interference, and diffraction.
The amount of the electric field (E) is directly proportional to the magnitude of the magnetic field, with the relationship E = cB.
The universal constant of the velocity of electromagnetic waves in a vacuum is $\boxed{ \ c = 3 \times 10^8 \ m/s. \ }$
The speed at which electromagnetic waves propagate depends merely on the electrical and magnetic properties of the medium that it travels on.
Because electromagnetic waves do not contain an electric charge, they do not experience any possible deviation in the electric or magnetic fields.

<h3>Further explanation</h3>

Two physicists who contributed significantly to developing the concept of electromagnetic waves are Faraday and Maxwell around 1831-1864.
From the observations, Faraday suggested that changes in the magnetic field cause an electric charge to flow in the loop of wire, contributing in the emergence of an electric field.
Maxwell proposed a reverse process, which is a change in the electric field will generate a magnetic field.
As follows, according to Faraday's Law, changes in sinusoidal magnetic fields generate electric fields which also change sinusoidally.
Meantime, according to Maxwell's Hypothesis, changes in sinusoidal electric fields generate magnetic fields which also change sinusoidally.
Furthermore, there is a process of combining electric and magnetic fields that propagate in all directions called electromagnetic waves.

<h3>Learn more </h3>

About vector components brainly.com/question/1600633
Determine the shortest wavelength in electron transition brainly.com/question/4986277
Particle's speed and direction of motion brainly.com/question/2814900

Keywords: the characteristics, electromagnetic waves, transverse, vacuum, electric fields, magnetic, perpendicular, propagation, Maxwell, Faraday, the speed, polarization, reflection, refraction, interference, and diffraction

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Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th

DiKsa [7]

Answer:

a. $\rm -1.49\ m/s^2.$

b. $\rm 50.49\ m.$

Explanation:

<u>Given:</u>

Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

$\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).$

At time t = 3 seconds,

$\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.$

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

$\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.$

For the time interval of 2 seconds,

$\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt$

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

$\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.$

It is the displacement of the particle in 2 seconds.

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3 years ago

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Rom4ik [11]

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