Answer:
Explanation:
The equation for this is
f = μ
where f is the frictional force the block needs to overcome, μ is the coefficient of static friction, and
(that means that the normal force is the same as the weight of the block which has an equation of weight = mass times the pull of gravity). Filling in:
1.09 = μ(.413)(9.8) and
μ =
so
μ = .27
E=274J
h=140cm=1,4m
g≈9,8m/s²
m=?
E=mgh
m=E/gh=274J/9,8m/s²*1,4m≈20kg
"Non nobis Domine, non nobis, sed Nomini tuo da gloriam."
Regards M.Y.
Answer:
the answer is D
Explanation:
Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.
Answer:
2
Explanation:
We know that in the Fraunhofer single-slit pattern,
maxima is given by

Given values
θ=2.12°
slit width a= 0.110 mm.
wavelength λ= 582 nm
Now plugging values to calculate N we get

Solving the above equation we get
we N= 2.313≅ 2