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lbvjy [14]
2 years ago
15

Consider the uniform electric field E = (8.0ĵ + 2.0 ) ✕ 103 N/C. What is its electric flux (in N · m2/C) through a circular area

of radius 9.0 m that lies in the xy-plane? (Enter the magnitude.)
Physics
1 answer:
cluponka [151]2 years ago
4 0

Answer:

5.09 x 10⁵ Nm²/C

Explanation:

The electric flux φ through a planar area is defined as the electric field Ε times the component of the area Α perpendicular to the field. i.e

φ = E A

From the question;

E = (8.0j + 2.0k) ✕ 10³ N/C

r = radius of the circular area = 9.0m

A = area of a circle = π r²           [Take π = 3.142]

A = 3.142 x 9² = 254.502m²

Now, since the area lies in the x-y plane, only the z-component of the electric field is responsible for the electric flux through the circular area.

Therefore;

φ = (2.0) x 10³ x 254.502

φ = 5.09 x 10⁵ Nm²/C

The electric flux is 5.09 x 10⁵ Nm²/C

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Answer:

Explanation:

The equation for this is

f = μF_n where f is the frictional force the block needs to overcome, μ is the coefficient of static friction, and F_n = w=mg (that means that the normal force is the same as the weight of the block which has an equation of weight = mass times the pull of gravity). Filling in:

1.09 = μ(.413)(9.8) and

μ = \frac{1.09}{(.413)(9.8)} so

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"Non nobis Domine, non nobis, sed Nomini tuo da gloriam."



Regards M.Y.
3 0
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g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for
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2

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