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Butoxors [25]
3 years ago
8

A ball, which has a mass of 1.25 kg, is thrown straight up from the top of a building 225 meters tall with a velocity of 52.0 m/

s. what will be the momentum of this ball just as it reaches the ground
Physics
1 answer:
Elena-2011 [213]3 years ago
6 0

First we will find the speed of the ball just before it will hit the floor

so in order to find the speed of the cart we will first use energy conservation

KE_i + PE_i = KE_f + PE_f

\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv_f^2 + 0

\frac{1}{2}(1.25)(52)^2 + 1.25(9.8)(225) = \frac{1}{2}(1.25)v_f^2

So by solving above equation we will have

v_f = 84.3 m/s

now in order to find the momentum we can use

P = mv

P = 1.25 \times 84.3

P = 105.4 kg m/s

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Arrange the following types of electromagnetic radiation in order of increasing (lowest to highest) frequency from left to right
algol13

Electromagnetic radiation in order of increasing (lowest to highest) frequency is Radio waves < Green visible light < UV radiation.

<h3>What is Frequency?</h3>

This is defined as the rate at which something occurs or is repeated over a particular period of time. The unit of frequency is referred to as Hertz.

Electromagnetic radiations with increasing frequency can be seen below:

Radio waves, microwaves, infrared waves, visible light, ultraviolet radiations, X rays, γ rays.

Read more about Frequency here brainly.com/question/254161

4 0
2 years ago
How long does it take an object to travel 375 m at a rate of 25 m/s?
Leni [432]

Answer:

15s

Explanation:

Given parameters:

Distance traveled  = 375m

Speed = 25m/s

Unknown:

Time taken = ?

Solution:

To solve this problem, we make time the subject of the speed equation.

    Speed  = \frac{distance}{time}  

  Time  = \frac{distance}{speed}  

 Now insert the parameters and solve;

  Time  = \frac{375}{25}   = 15s

3 0
3 years ago
A 500kg car is driven forward with a thrust force of 1500N. Air resistance and friction acts against the motion of the car with
Wittaler [7]
2m/s^2, this is because F=ma, meaning a is also equal to F/m. The car applies 1500N in one direction and outside sources apply a total of -500N, meaning the 500kg car is moving forward with a total of 1000N of force. Taking the total 1000N and dividing it by 500kg gives you and acceleration of 2m/s^2. Hope this helps!
8 0
2 years ago
The water flowing through a 2.0 cm (inside diameter) pipe flows out through three 1.3 cm pipes. (a) If the flow rates in the thr
Verdich [7]

Answer:

a)54L/min

b)0.845

Explanation:

a) A x V=A_1V_1+ A_2V_2+A_3V_3

where suffix 1,2,3 refers to the three pipes.

            =27L/min+16L/min+11 L/min

            =54L/min

b) A x V=54L/min => \frac{\pi }{4} d^2 x v

   d= 2 cm

\frac{\pi }{4} d^2 x v = 54

v= \frac{4}{\pi } x \frac{54}{2^2}

-> A_1 x V_1=27L/min => \frac{\pi }{4} d_1^2 x v_1

d_1= 1.3cm

\frac{\pi }{4} d^2 x v_1 = 27

v_1= \frac{4}{\pi } x \frac{27}{1.3^2}

Next is to find the ratio of speed i.e \frac{v}{v_1}

\frac{4}{\pi } x \frac{54}{2^2} / \frac{4}{\pi } x \frac{27}{1.3^2} => \frac{54}{27} \frac{1.3^2}{2^2}

\frac{v}{v_1}= 0.845

8 0
3 years ago
½H2(g) + ½I2(g) → HI(g), ΔH = + 26 kJ/mole 117 kJ/mole + C(s) + 2S(s) → CS2(g) The temperature of the surroundings will:
Alona [7]
From the above reaction the temperature of the surroundings will increase.
8 0
3 years ago
Read 2 more answers
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