Answer:
a = ω^2 A formula for max acceleration (ignoring sign)
V = ω A formula for max velocity
V^2 = ω^2 A^2 = a A from first equation
E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J
(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule
The solution you should use is Hooke's law: F=-kx
It should have the same signs because they repel due to the stretch of the spring.
a. Since there is a constant energy within the spring, then Hooke's law will determine the possible algebraic signs. The solution should be
<span>F = kx
270 N/m x 0.38 m = 102.6 N
</span>
b. Then use Coulomb's law; F=kq1q2/r^2 to find the charges produced in the force.
Answer:
a) Current = 11 mA
b) Energy = 66 mJ
c) Power = 101.54 W
Explanation:
a) Voltage, V = IR
Voltage, V = 6 V, Resistance, R = 550 Ω
Current, I 
b) Energy = Current x Voltage = 6 x 0.011 = 0.066 J = 66 mJ
c) 
As per Newton's law of inertia we can say every object will move in its state of motion either in the state of rest or will move with same constant velocity until some unbalanced external force will act upon it
so here we have to fill the space which says that stationary object can start or moving object will change its direction only in which case
so here the correct answer should be Unbalanced Force condition we will obtain such situation.
so we have
<u>Unbalance force</u> can cause a stationary object to start moving or a moving object to change its speed or direction or both.
