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Vsevolod [243]
2 years ago
8

A helicopter is hovering at a constant height of 35 m. The upward lift force on the helicopter is 85500. What is the weight of t

he helicopter
Physics
1 answer:
Vika [28.1K]2 years ago
7 0
2,442! I think..right ok
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11) A sled is initially given a shove up a frictionless 35º incline. It reaches a maximum height of 2.5
Andrej [43]

Answer:

7 m/s

Explanation:

To solve this problem you must use the conservation of energy.

K1 +U1=K2+U2

That math speak for, initial kinetic energy plus initial potential energy equals final kinetic energy plus final potential energy.

The initial PE (potential energy) is 0 because it hasn't been raised in the air yet. The final KE (kinetic energy) is 0 because it isn't moving. This gives the following:

KE1= \frac{1}{2}mv^{2}}

PE2=mgh

K1=U2

\frac{1}{2} mv^{2} =mgh

Solve for v

v=\sqrt{2gh}

Input known values and you get 7 m/s.

5 0
2 years ago
How many (whole number of) 87 kg people
choli [55]

Answer:

11

Explanation:

1. You are going to be rounding down.

2. change the metric ton to kg.

1.000 * 10^3 kg = 1000 kg

1000 / 87 = 11.49 = 11 people

6 0
3 years ago
What is Marie's instantaneous speed at 20 minutes in miles/min?
AVprozaik [17]

Answer:

0.25miles/min

Explanation:

Instantaneous speed of a person or an object is its speed at a particular moment usually at a period of time.

The speedometer of a car reports the instantaneous speed.

 It can be mathematically expressed as;

        Instantaneous speed  = \frac{distance}{time}

At 20min the distance covered is 5miles;

    Instantaneous speed  = \frac{5 miles }{20mins}   = 0.25miles/min

8 0
3 years ago
A student places his hand in front of a plane mirror as shown in the diagram. Which terms correctly describe the image that the
ANTONII [103]
Either A or D but maybe D
4 0
2 years ago
The length of the track itself is 500m. The vehicles (each of mass 15kg) are dragged
gogolik [260]

Answer:

W = 100000 J = 100 KJ

Explanation:

Here we will use the most basic and general formula of work, which is as follows:

W = Fd

where,

W = Work Done = ?

F = Force Required = 200 N

d = Length of Track = 500 m

Therefore,

W = (200\ N)(500\ m)\\

<u>W = 100000 J = 100 KJ</u>

5 0
2 years ago
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