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Butoxors [25]
3 years ago
14

When a pendulum is at the position all the way to the left when it is swinging (at the top of the arc), what is true of the kine

tic and potential energy?
Physics
2 answers:
Nadusha1986 [10]3 years ago
8 0
Potential energy + kinetic energy = constant at every moment in time

At the highest point:

potential energy is at its maximum 
kinetic energy is zero
Masteriza [31]3 years ago
4 0

Answer:

Kinetic energy(1/2mV²) = 0

Potential energy is converted to kinetic energy (mgh = 1/2mv²)

Explanation:

kinetic energy of an object or body has to do with the motion of the object/body at that point

Kinetic energy = 1/2MV²

The kinetic energy of the pendulum at the top of the arc is 0, this invariably means that there's no velocity of the pendulum at that point which makes it 0 (static). The Potential energy is converted to kinetic energy when the pendulum starts moving in the opposite direction after this period.

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Two bicycle tires are set rolling with the same initial speed of 3.30 m/s along a long, straight road, and the distance each tra
vredina [299]

Answer:

At low pressure- \mu_{k}=0.02315

At high pressure- \mu_{k}=0.00445

Explanation:

Initial speed, V_{i}=3.3 m/s

Final speed, V_{f}=3.3/2= 1.65 m/s

Net horizontal force due to rolling friction F_{net}=\mu_{k} mg where m is mass, g is acceleration due to gravity, \mu_{k} is coefficient of rolling friction

From kinematic relation, V_{f}^{2}- V_{i}^{2}=2ad

For each tire,

V_{f}^{2}- V_{i}^{2}=2\mu_{k}gd

Making \mu_{k} the subject

\mu_{k}=\frac {V_{f}^{2}- V_{i}^{2}}{2gd}

Under low pressure of 40 Psi, d=18 m

\mu_{k}=\frac {1.65^{2}- 3.3^{2}}{2*9.8*18}=-0.02315

Therefore, \mu_{k}=0.02315

At a pressure of 105 Psi, d=93.7

\mu_{k}=\frac {1.65^{2}- 3.3^{2}}{2*9.8*93.7}=-0.00445

Therefore, \mu_{k}=0.00445

4 0
3 years ago
During what era did the French and Indian War occur?
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A cylindrical tungsten filament 14.0 cmcm long with a diameter of 1.00 mmmm is to be used in a machine for which the temperature
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Answer:

Resistivity ρ=1.12 x 10^-4 Ωm

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