11. 2 cm of rain falls in 10 minutes. The rain fall

The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration, skidding to a comp

Ber [7]

Answer: $-6.80\ ms^{-2}$

Explanation:

We know that the formula for acceleration is given by:

$a=\dfrac{v-u}{t}$ , where v = Final velocity

u= Initial velocity

Given : The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration.

i.e. u= 110 km/h $=\dfrac{110\times1000}{3600}\approx35.6\ m/s$ [∵ 1 km= 100 meters and 1 hour = 3600 seconds]

v= 0 m/s ( At brake , final velocity becomes 0)

t=4.5 seconds

Substitute all the values in the formula , we get

$a=\dfrac{0-30.56}{4.5}\approx-6.80\ ms^{-2}$

Hence, the average acceleration of the car during braking is $-6.80\ ms^{-2}$ .

5 0

3 years ago

What is the biggest star in our universe?

oksano4ka [1.4K]

VY Canis Majoris is the largest star ever discovered.

7 0

3 years ago

Describe how the basic measurements of length, volume, and mass were determined in the

Anna11 [10]

the basic measurements of length, volume, and mass are 1 meter, 1 meter³ and 1kilogram.

One 10-millionth of the distance from the North Pole to the equator would equal one meter.

A cube with sides of one meter has a volume of one meter³.

The mass of 1,000 cubic centimeters of water is very close to (and was originally intended to be exactly) one kilograms.

but today a more precise way to define is available in which:

1 meter is defined as the distance traveled by light in 1/3×10⁸ sec.

The weight of a specific platinum-iridium prototype held by the International Bureau of Weights and Measures is defined as 1 kg.

moreover these measurements are man made and are not absolute and therefore many new units of measurement can be defined as long as they are fundamentally same everywhere.

learn more about metric system here:

brainly.com/question/2555957

#SPJ9

4 0

1 year ago

Please awnser and show the ways

topjm [15]

Answer:

Answers in solutions.

Explanation:

Question 6:

The density of gold is 19.3 g/cm³

The density of silver is 10.5 g/cm³

The density of the substance in Crown A;

Density = mass ÷ volume = $\frac{1930}{100}$ = 19.3 g/cm³

Since the density of gold, given, is 19.3 g/cm³ and the density of the substance in Crown A has a density of 19.3 g/cm³ , then that substance must be gold.

The density of the substance in Crown B;

Density = mass ÷ volume = 1930 ÷ 184 = 10.48913043 g/cm³ ≈ 10.5 g/cm³ (answer rounded up to one decimal place)

Since the density of the substance in Crown B is approximately equal to 10.5 g/cm³ , then that substance is Silver.

The density of substance in Crown C;

Density = mass ÷ volume = 1930g ÷ 150cm³ = 12.86666667 ≈ 12.9 cm³ (answer rounded up to one decimal place)

<h3>The density of the mixture:</h3><h3 />

For 2 cm³ of the mixture, its mass equal 19.3 g + 10.5 g = 29.8 g

∴ for 1 cm³ of the mixture, its mass equal to $\frac{29.8}{2}$ = 14.9 g

Hence the density of the mixture = 14.9 g/cm³ and is not equal to the density of the substance in Crown C.

* Crown C is not made up of a mixture of gold and silver.

Question 7:

An empty masuring cylinder has a mass of 500 g.

Water is poured into measuring cylinder until the liquid level is at the 100 cm³ mark.

The total mass is now 850 g

The mass of water that occupied the 100 cm³ space of the container = total mass - mass of the empty container = 850 g - 500 g = 350 g

Density of the liquid (water) poured into the container = mass ÷ volume = 350 g ÷ 100 cm³ = 3.5g/cm³

Question 8:

A tank filled with water has a volume of 0.02 m³

(a) 1 liter = 0.001 m³

How many liters? = 0.02 m³ ?

Cross multiplying gives:

$\frac{0.02 * 1}{0.001}$ = 20 liters

(b) 1 m³ = 1,000,000 cm³

0.02 m³ = how many cm³ ?

Cross-multiplying gives;

$\frac{0.02 * 1,000,000}{1}$ = 20,000 cm³

(c) 1 cm³ = 1 ml

∴ 0.02 m³ of the water = 20,000 cm³ = 20,000 ml

Question 9:

Caliper (a) measurement = 3.2 cm

Caliper (b) measurement = 3 cm

Question 10:

A stone is gently and completely immersed in a liquid of density 1.0 g/cm³
in a displacement can
The mass of liquid which overflow is 20 g

The mass of the liquid which overflow = mass of the stone = 20 g

1 gram of the liquid occupies 1 cm³ of space.

20 g of the liquid will occupy; $\frac{20 * 1}{1}$ = 20 cm³

(a) Since the volume of the water displaced is equal to the volume of the stone.

∴ The volume of the stone = 20 cm³

(b) Mass = density × volume

Density of the stone = 5.0 g/cm³

Volume of the stone = 20 cm³

Mass of the stone = 5 g/cm³ × 20 cm³ = 100 g

7 0

3 years ago

In our Solar System, the inner planets are rocky because Choose one: A. warm temperatures in the inner disk caused the inner pla

xeze [42]

The inner planets are rocky because The warm temperatures in the inner disk caused the inner planetesimals to be formed of mostly rocky material.

What are rocky planets?

Rocky planets are the planet in which constituents are mostly silicate rocks or metal. They are also regarded as a planet with a solid surface.
The formation of rocky planets is said to have occurred billions of years ago and its process of formation is termed accretion. Through accretion are its constituents formed as the more it goes bigger, the higher the rising temperature and pressure in its core and the elements which have to undergo accreted heat up, melt, and spread. Through this process, heavier elements go deeper into the core of the planet and lighter elements float toward the surface.
In the formation of rocky planets, the inner portions of the disk are said to be warm from the protostar thereby resulting in the production of the heavy elements that stay there.

Examples of rocky planets are Earth or Mars

Hence, from the above, we can say that,

The warm temperatures in the inner disk caused the inner planetesimals to be formed of mostly rocky material.

Here,

Option A is correct.

Learn more about rocky planets here:

brainly.com/question/22392798

#SPJ4

3 0

2 years ago