Question

2. A sample of gas has a pressure of 1.4 atm and a volume of 500 mL. If the volume is decreased to 250 mL, what is the new pressure?

Answer 1

Answer: The new pressure is 2.8 atm.

Explanation:

Since our given information only involves pressure and volume, we will use Boyle's Law: $P_{1} V_{1} =P_{2} V_{2}$. Let's input the data into the formula.

$1.4atm*500mL=P_{2} *250mL$

We have to rearrange our data a bit now because the volume is supposed to be in liters. To convert from milliliters(mL) to liters(L), you must divide the number by 1000. That is what we will do with both of our given volumes.

$\frac{500mL}{1000} =0.5L$     $\frac{250mL}{1000} =0.25L$

Now that our volumes are in liters, we can correctly plug in our data.

$1.4atm*0.5L=P_{2} *0.25L$

Since we do not know the value $P_{2}$, we must rearrange the formula into a stoichiometric equation to find out the answer.

$P_{2}=\frac{1.4atm*0.5L}{0.25L}$    $P_{2}=2.8 atm$

Our final answer is 2.8 atmospheres.

I hope this helps!! Pls mark brainliest :))