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REY [17]
3 years ago
7

How small are the microorganisms that live on and in the human body? Answer it in at least 1 paragraph

Chemistry
2 answers:
Lera25 [3.4K]3 years ago
8 0

Answer:

The human body contains trillions of microorganisms — outnumbering human cells by 10 to 1. Because of their small size, however, microorganisms make up only about 1 to 3 percent of the body's mass (in a 200-pound adult, that's 2 to 6 pounds of bacteria), but play a vital role in human health.

lorasvet [3.4K]3 years ago
6 0

Answer: <u>The human body contains trillions of microorganisms — dwarfing human cells by 10 to 1. Due to their little size, nonetheless, microorganisms make up just around 1 to 3 percent of the weight's (in a 200-pound grown-up, that is 2 to 6 pounds of microscopic organisms), yet assume a crucial function in human wellbeing.  In 2016, a survey of over forty years of examination into the human microbiome found that there is zero logical proof to back this frequently refered to tidbit up. Rather, the proportion appears to be about 1.3-to-1, with the normal human playing host to around 100 trillion microorganisms, plus or minus. Rather, the proportion seems to be about 1.3-to-1, with the normal human playing host to around 100 trillion organisms, plus or minus. </u>

<u />

Explanation:

You can mix this up and paraphrase this into ur own words.

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At standard temperature and pressure. 0.500 mole of xenon gas occupies
ANEK [815]

Answer:

0.500 mole of Xe (g) occupies 11.2 L at STP.

General Formulas and Concepts:

<u>Gas Laws</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

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  • Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

0.500 mole Xe (g)

<u>Step 2: Convert</u>

  1. [DA] Set up:                                                                                                  \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)
  2. [DA] Evaluate:                                                                                               \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}

Topic: AP Chemistry

Unit: Stoichiometry

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