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balu736 [363]
2 years ago
8

Expand and simplfy (2x+1)(x+3)

Mathematics
1 answer:
Nina [5.8K]2 years ago
5 0

Answer:

(2x+1)(x+3)

2x(x+3)+1(x+3)

2x2+6x+x+3

2x2+7x+3 (2x2 means two x square)

if you want you can also multiply 2x+3 by x+3

like this:

(2x+1)(x+3)

x(2x+1)+3(2x+1)

2x2+x+6x+3

2x2+7x+3 (2x2 means two x square)

They will both give you the same answer.

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Why is it important to a lending institution that a person present a 2-year job history when applying for a home loan? a. Most l
Paraphin [41]

The answer would be D. When it comes to home loans, having a good payment record and a decent job history is important. It is in this way that lenders are going to have the assurance they need with regards to being paid back on time with the money they lent. 

3 0
2 years ago
ABCD is a parallelogram. AB>AD. Prove: m∠ADB>m∠BDC. Show your work (statement reason maybe?)
Gwar [14]

In the parallelogram ABCD, join BD.

Consider the triangle Δ ABD.

It is given that AB > AD.

Since, in a triangle, angle opposite to longer side is larger, we have,

∠ ADB > ∠ ABD. --- (1)

Also, AB || DC and BD is a transversal.

Therefore,

∠ ABD = ∠ BDC

Substitute in (1), we get,

∠ ADB > ∠ BDC.

7 0
3 years ago
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Evaluate sigma 12 n=3-5n-1
Leni [432]
12n = 3-5n-1 or n =3-5n-1???

6 0
2 years ago
Eric throws a biased coin 10 times. He gets 3 tails. Sue throw the same coin 50 times. She gets 20 tails. Aadi is going to throw
iren2701 [21]

Answer:

(1) The correct option is (A).

(2) The probability that Aadi will get Tails is \frac{2}{5}.

Step-by-step explanation:

It is provided that:

  • Eric throws a biased coin 10 times. He gets 3 tails.
  • Sue throw the same coin 50 times. She gets 20 tails.

The probability of tail in both cases is:

  • P(\text{Tail})=\frac{3}{10}
  • P(\text{Tail})=\frac{20}{50}=\frac{2}{5}

(1)

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

In this case we need to compute the proportion of tails.

Then according to the Central limit theorem, Sue's estimate is best because she throws it <em>n = </em>50 > 30 times.

Thus, the correct option is (A).

(2)

As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:

P(\text{Tail})=\frac{20}{50}=\frac{2}{5}

Thus, the probability that Aadi will get Tails is \frac{2}{5}.

7 0
3 years ago
Read 2 more answers
Enter the missing numbers in the boxes to complete the table of equivalent ratios of time to distance.
andre [41]
Answer:  Here is the complete table, with the filled in values:
______________________________________________________________
Time (h)    Distance (mi)
    3                2 
    9                6
   12                8
   18               12
___________________________________________________

Explanation:
___________________________________________________
Let us begin by obtaining the "?" value; that is, the "distance" (in "mi.") ;
         when the time (in "h") is "18" ; 
___________________________________________________

12/8 = 18/?  

Note: "12/8 = (12÷4) / (8÷4) = 3/2 ;

Rewrite:  3/2 = 18/? ;  cross-multiply:  3*? = 2 * 18 ; 
                                                                        3*? = 36 ;

                                                                      Divide each side by "3" ;
                                                                            The "?" = 36/3 = 12 ;

So, 12/8 = 18/12 ;

The value: "12" takes the place for the "?" in the table for "distance (in "mi.);
                              when the "time" (in "h") is "18".
__________________________________________________________
Now, let us obtain the "? " value for the "distance" (in "mi.");
                when the "time" (in "h") is:  "9" .

12/8 = 9/? ;  Solve for "?" ;

We know (see aforementioned) that "12/8 = 3/2" ; 

So, we can rewrite:  3/2 = 9/? ;  Solve for "?" ; 

Cross-multiply:  3* ? = 2* 9 ;    3* ? = 18 ;  
                                                           Divide each side by "3" ;
                                                    to  get:  "6" for the "?" value.

When the time (in "h") is "9", the distance (in "mi.") is "6" .
____________________________________________________
Now, to solve the final "?" value in the table given.

9/6 = ?/2 ;  Note:  We get the "6" from our "calculated value" (see above problem). 

9/6 = (9÷3) / (6÷3) = 3/2 ;  

So, we know that the "?" value is:  "3" .

Alternately:   9/6 = ?/2 ; 

Cross-multiply:  6*? = 2*9 ;   6 * ? = 18 ;  Divide each side by "6" ;
                                                               to find the value for the "?" ; 
                                                                    "?" = 18/6 = "3" .

When the "distance" (in "mi.") is:  "2" ;  the time (in "h") is:  "3" .
____________________________________________________
Here is the complete table—with all the values filled in:
____________________________________________________

<span>Time (h)    Distance (mi)
____________________________________________________
    3                2 
    9                6
   12                8
   18               12
____________________________________________________
</span>
6 0
3 years ago
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