Heya!
For this problem, use the formula:
s = Vo * t + (at^2) / 2
Since the initial velocity is zero, the formula simplifies like this:
s = (at^2) / 2
Clear a:
2s = at^2
(2s) / t^2 = a
a = (2s) / t^2
Data:
s = Distance = 518 m
t = Time = 7,48 s
a = Aceleration = ¿?
Replace according formula:
a = (2*518 m) / (7,48 s)^2
Resolving:
a = 1036 m / 55,95 s^2
a = 23,34 m/s^2
The aceleration must be <u>23,34 meters per second squared</u>
Answer:22.22m/s
Explanation:
Answer: 22.22 m/s
Explanation:
Using the law of conservation of momentum:
Initial momentum of the system = final momentum of the system.
mu+m'u' = mv+m'v'
where u and u' are the initial velocities.
v and v' are the final velocities.
mass of bullet, m = 0.04 kg
mass of the block of wood, m' = 0.5 kg
initial velocity of bullet, u = 300 m/s
initial velocity of block, u' = 0
after collision, block and bullet would move together with velocity v
⇒0.04 kg × 300 m/s + 0 = 0.54 kg × v
⇒ v = 22.22 m/s
Thus, the bullet and the wood block move together as one object with the speed 22.2 m/s.
Answer:
Gamma rays
Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies.
Explanation:
P = F/A
P = mg/A [ since F = mg ]
P = Vdg/A [ since m = Vd ]
P = Ahdg/A [ since V = Ah ]
P = hdg
To solve this problem it is necessary to apply the concepts of Work. Work is understood as the force applied to travel a determined distance, in this case the height. The force in turn can be expressed by Newton's second law as the ratio between mass and gravity, as well
Where,
m = mass
h = height
g = Gravitational constant
When it ascends to the second floor it has traveled the energy necessary to climb a height, under this logic, until the 4 floor has traveled 3 times the height h of each of the floors therefore
Replacing in our equation we have to
The correct answer is 4.
