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3 years ago

Is matter lost when a candle is burned

Chemistry

2 answers:

jeka943 years ago

6 0

No it isnt lost.

hope this helps you

zlopas [31]3 years ago

5 0

No it is redistributed and the state changes to gas and liquid

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Calculate the molarity of a solution prepared by dissolving 6.80 grams of AgNO3 in 2.50 liters of solution.

tester [92]

Answer:

0.016M

Explanation:

First we find the mole of AgNO3 by using the formula mass/molar mass..

Then we find molarity by the formula mole/volume...

I hope you get this..

7 0

3 years ago

If this decay has a half life of 2.60 years, what mass of 72.5 g of sodium 22 will remain after 15.6 years

Vlad1618 [11]

Sodium-22 remain : 1.13 g

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually, radioactive elements have an unstable atomic nucleus.

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

half-life = t 1/2=2.6 years

T=15.6 years

No=72.5 g

$\tt Nt=72.5.\dfrac{1}{2}^{15.6/2.6}\\\\Nt=72.5.\dfrac{1}{2}^6\\\\Nt=1.13~g$

8 0

3 years ago

A tau lepton decays into an electron, an electron antineutrino and a tau neutrino. Write out this reaction in symbolic (equation

Dmitry [639]

Answer:

Explanation:

hhidhwvagaue hrurifv3v2vd

5 0

3 years ago

The number of grams per mole of something is also known as_______

Sergeeva-Olga [200]

Answer:

Molar mass

Explanation:

This is a counting unit which represents the mass in grams of a substance that make up one mole of the substance. This mass is calculated as follows:

Molar mass = Mass/ Number of moles

Units: grams/mol

5 0

3 years ago

Read 2 more answers

The ka of phosphoric acid, h3po4, is 7.6  10–3 at 25 °c. for the reaction h3po4(aq) h2po4 – (aq) + h+ (aq) ∆h° = –14.2 kj/mol.

blsea [12.9K]

<span>Use the van't Hoff equation: ln ( K2 K1 ) = Î” HÂş R ( 1 T1 â’ 1 T2 ) ln ( K2 7.6*10^-3 ) = -14,200 J 8.314 ( 1 298 â’ 1 333 ) ln ( K2 7.6*10^-3 ) = â’ 1708 ( 0.00035 ) ln ( K2 0.0076 ) = â’ 0.598 Apply log rule a = log b b a -0.598 = ln ( e â’ 0.598 ) = ln ( 1 e 0.598 ) Multiply both sides with e^0.598 K 2 e 0.598 = 0.0076 K e 0.598 e 0.598 = 0.0076 e 0.598 K 2 = 0.0076 e 0.598 = 4.2 â‹… 10 â’ 3 K2 = 4.2 â‹… 10 â’ 3</span>

7 0

3 years ago