this is a binomial problem: p = 0.7 and q = 0.3
a) (0.7)^6
b) (6C4)(0.7)^4(0.3)^2
c) Pr ( at least 4) = Pr(4) + Pr(5) + Pr(6) = (6C5)(0.7)^5(0.3) + (0.7)^6
d) Pr (no more than 4) = 1 - Pr(at least 4) = 1 - (answer from c)
Answer:
B
Step-by-step explanation:
The answer is B because Uniform distributions are probability distributions with equally likely <u>outcomes</u>. In a discrete uniform distribution,<u> outcomes</u> are discrete and have the same probability. In a continuous uniform distribution, outcomes are continuous and infinite. In a normal distribution, data around the mean occur more frequently.
Answer:
For 10 tosses we have that E(X)=10
Therefore E(i)= 1/10 +2/10 +3/10....10/10
This implies that 40/10=E(i)
Therefore E(10) =40/10
= 4.
Im assuming this is a True or false question ive answered the same question and its True.
Answer:
Step-by-step explanation:
We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:
In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:
Since the area of a square is the side length square then...
The square root and the squared cancel out giving us...