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e-lub [12.9K]
3 years ago
15

How many formula units of silver fluoride, AgF, are equal to 42.15 g f this substance?

Chemistry
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

1.99 x 10²³ formula units

Explanation:

Given parameters:

Mass of AgF  = 42.15g

Unknown:

The amount of formula units

Solution:

To solve this problem, we set out by find the number of moles in this compound from the given mass.

   Number of moles  = \frac{mass}{molar mass}

molar mass of AgF  = 107.9 + 19  = 126.9g/mol

  Number of moles  = \frac{42.15}{126.9}   = 0.33 moles

       1 mole of a substance =  6.02 x 10²³ formula units

         0.33 moles of AgF  = 0.33 x 6.02 x 10²³  = 1.99 x 10²³ formula units

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The fermentation of glucose (C6H12O6) produces ethyl alcohol (C2H5OH) and CO2:
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To answer your question I will use dimensional analysis, which is used by cancelling out the units. I will also use the balanced equation provided as a conversion factor.

A) First start out with the 0.300 mol of C6H12O6...
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*The significant figures (sig figs) at still three, the 2 is a conversion counting number and does not count*

B) First change 2.00 g of C2H5OH to moles of C2H5OH...
The molecular mass of C2H5OH is...
2(12.01 g/mol) + 5(1.008 g/mol) + 16.00 g/mol + 1.008 g/mol = 46.07 g/mol
This can be used as a conversion factor to change grams to moles. 
2.00 g C2H5OH * (1 mol C2H5OH / 46.07 g C2H5OH) = 0.0434 mol C2H5OH

Second, you can change the moles of C2H5OH to moles of C6H12O6..
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Third, change moles of C6H12O6 to grams...
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I hope this helped and I am sorry that I talked to much, I just didn't want to miss anything!
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<u>Answer:</u> The volume of barium chlorate is 195.65 mL

<u>Explanation:</u>

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Putting values in above equation, we get:

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