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3 years ago

How many formula units of silver fluoride, AgF, are equal to 42.15 g f this substance?

Chemistry

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer:

1.99 x 10²³ formula units

Explanation:

Given parameters:

Mass of AgF = 42.15g

Unknown:

The amount of formula units

Solution:

To solve this problem, we set out by find the number of moles in this compound from the given mass.

Number of moles = $\frac{mass}{molar mass}$

molar mass of AgF = 107.9 + 19 = 126.9g/mol

Number of moles = $\frac{42.15}{126.9}$ = 0.33 moles

1 mole of a substance = 6.02 x 10²³ formula units

0.33 moles of AgF = 0.33 x 6.02 x 10²³ = 1.99 x 10²³ formula units

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Given,

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Learn more about internal energy here:

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