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3 years ago

How many formula units of silver fluoride, AgF, are equal to 42.15 g f this substance?

Chemistry

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer:

1.99 x 10²³ formula units

Explanation:

Given parameters:

Mass of AgF = 42.15g

Unknown:

The amount of formula units

Solution:

To solve this problem, we set out by find the number of moles in this compound from the given mass.

Number of moles = $\frac{mass}{molar mass}$

molar mass of AgF = 107.9 + 19 = 126.9g/mol

Number of moles = $\frac{42.15}{126.9}$ = 0.33 moles

1 mole of a substance = 6.02 x 10²³ formula units

0.33 moles of AgF = 0.33 x 6.02 x 10²³ = 1.99 x 10²³ formula units

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1.63 moles since 1 mole is equal to 136.4332 grams

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4 years ago

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determine the final temperature of a gold nugget parentheses Mass equals 376 G parentheses that starts at 398k and loses 4.85 KJ

maw [93]

Answer:

297.23 K

Explanation:

Given that:

the mass of the gold nugget (m) = 376 g

the initial temperature $T_1$ = 398 K

amount of heat lost Q = -4.85 kJ = -4.85 × 10³

specific heat capacity (c) = 0.128 J/g° C

Using the formula for calculating the Heat energy

$Q = mc\Delta T \\ \\ Q = m\times c\times (T_2-T_1)$

$-4.85 \times 10^3 = 376 \times 0.128 \times (T_2 - 398) \\ \\ -4.85\times 10^3 = 48.128(T_2 - 398) \\ \\ \dfrac{-4.85\times 10^3}{48.128}= (T_2 - 398) \\ \\-100.77 = T_2 -398\\\\T_2 = -398 +100.77\\ \\ \mathbf{ T_2 = 297.23K}$

7 0

3 years ago

A tank at is filled with of dinitrogen monoxide gas and of boron trifluoride gas. You can assume both gases behave as ideal gase

blsea [12.9K]

Answer:

(1). Mole fraction = 0.152 for sulfur tetrafluoride gas.

Mole fraction = 0.848 For dinitrogen monoxide gas.

(2). Partial Pressure for dinitrogen monoxide gas = 187 kPa

Partial Pressure for sulfur tetrafluoride gas = 33.4 kpa.

(3). Total Partial Pressure = 220.4 kpa.

Explanation:

So, we are given the following data or parameters or information in the question above;

• Volume of the tank = 5.00L per tank;

• Temperature of the tank = 7.03°C;

• The mass of the content in the tank =

17.7g of dinitrogen monoxide gas and

7.77g of sulfur tetrafluoride gas.

So, we will be making use of the formulae below to calculate the MOLE FRACTION:

Moles, n= mass/molar mass and mole fraction = n(1)/ n(1) + n(2) per each constituents.

Moles, n1 = 17.7g of dinitrogen monoxide gas/ 44 grams per mole. =0.4023 moles.

Moles, n2 = 7.77g of sulfur tetrafluoride gas/ 108.1 grams per mole. = 0.07188 moles.

Total numbers of moles = n1 + n2 = 0.47415 moles

Mole fraction =0.4023 / 0.47415 = 0.848 of dinitrogen monoxide gas.

Mole fraction = 0.07188/0.47415 = 0.152 of sulfur tetrafluoride gas.

PART TWO: CALCULATE THE PARTIAL PRESSURE AND TOTAL PRESSURE BY USING THE FORMULA BELOW;

pressure × volume = number of moles × gas constant, R × temperature.

Pressure = n × R × T/ V.

For dinitrogen monoxide gas. ;

Partial Pressure = 0.4023 × 8.314 × 280.03 / 5 × 10^-3 = 187 kPa.

For sulfur tetrafluoride gas

Partial Pressure = 0.07188 × 8.314 ( × 280.03 / 5 × 10^-3. = 33.4 kpa.

(3). Total pressure = (187 + 33.4)kpa = 220.4 kpa

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