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Serhud [2]
3 years ago
11

What is the mass of a liquid that has a volume of 50.0ml and a density of 2.40g/ml?

Chemistry
1 answer:
Iteru [2.4K]3 years ago
5 0

Answer:

120g Using Density Equation.

Explanation:

Density =mass/volume

We need to the solve for the mass.

Mass=Density * Volume

Mass= 2.40 g/ml * 50.0 ml = 120g

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Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

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3 years ago
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Answer:

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Answer:

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Explanation:

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How do you know if your hypothesis is supported by your results or not?
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Answer:

Your hypothesis is an educated guess of what the end results of an experiment will be, using what you already know about your experiment you are going to conduct. So when you receive your final results, if your hypothesis is correct, or even somewhat correct then you know that it is supported by your results. For example, if I were to conduct the Coca-Cola and Mentos experiment, I could make a hypothesis that the Coca-Cola will have a bigger eruption when I add more than one Mento to the bottle due to a higher amount of a chemical with the addition of each mento. When I receive my results that the eruption was bigger each time, I know that my results supported my hypothesis.

Explanation:

-Hope this helped

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