Answer:
B) 7.7
Explanation:
For the reaction Ag2CO3(s) + CrO42‒(aq) → Ag2CrO4(s) + CO32‒(aq)
Kc = (CO₃²⁻) / (CrO₄²⁻)
and the Ksp given are
Ag₂CO₃ ⇒ 2 Ag⁺(aq) + CO₃²⁻(aq) Ksp₁ = (Ag⁺)²(CO₃²⁻)
Ag₂CrO₄ ⇒ 2 Ag⁺(aq)+ CrO₄²⁻(aq) Ksp₂ = (Ag⁺)²(CrO₄²⁻)
Where (...) indicate concentrations M
Notice if we divide the expressions for Ksp we get:
Ksp₁/Ksp₂ = (CO₃²⁻) / (CrO₄²⁻) = 8.5 x 10⁻¹² / 1.1 x 10⁻¹² = 7.7
which is the desired answer.
The correct answer is option a, that is, it gets broken down.
A set of metabolic reactions and procedures, which occurs in the cells of organisms to transform biochemical energy from nutrients into ATP, and then discharge waste components is known as cellular respiration. At the time of cellular respiration, a molecule of glucose gets dissociated slowly into water and carbon dioxide. With it, some of the ATP is generated directly in the reactions, which transform glucose.
135.1kPa
Explanation:
Given parameters:
T1 = 27°C
P1 = 101.325 kPa
T2 = 127°C
Unknown:
P2 = ?
Solution:
Using a derivative of the combined gas law where we assume that the gas has a constant volume, we can solve for the unknown.
At constant volume:
P1 is the initial pressure
T1 is the initial temperature
P2 is the final pressure
T2 is the final temperature
Take the given temperature to K
T1 = 27 + 273 = 300K
T2 = 127 + 273 = 400K
Input the variables:
P2 = 135.1kPa
learn more:
Boyle's law brainly.com/question/8928288
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Answer:
OB
Explanation:
tht is correct make me brainliest
Answer:
118
Explanation:
Of these 118 elements, 94 occur naturally on Earth. Six of these occur in extreme trace quantities: technetium, atomic number 43; promethium, number 61; astatine, number 85; francium, number 87; neptunium, number 93; and plutonium, number 94.
