Answer:
11.6mL of the 0.1400M NaOH solution
Explanation:
<em>0.154g of chloroacetic acid diluted to 250mL. Titrated wit 0.1400M NaOH solution.</em>
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The reaction of chloroacetic acid, ClCH₂COOH (Molar mass: 94.5g/mol) with NaOH is:
ClCH₂COOH + NaOH → ClCH₂COO⁻ + Na⁺ + H₂O
<em>Where 1 mole of the acid reacts per mole of the base.</em>
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That means the student will reach equivalence point when moles of chloroacetic acid = moles NaOH.
You will titrate the 0.154g of ClCH₂COOH. In moles (Using molar mass) are:
0.154g ₓ (1mol / 94.5g) = <em>1.63x10⁻³ moles of ClCH₂COOH</em>
To reach equivalence point, the student must add 1.63x10⁻³ moles of NaOH. These moles comes from:
1.63x10⁻³ moles of NaOH ₓ (1L / 0.1400moles NaOH) = 0.0116L of the 0.1400M NaOH =
<h3>11.6mL of the 0.1400M NaOH solution</h3>
Answer:
The given equation obey the law of conservation of mass.
Explanation:
Chemical equation:
2LiOH + CO₂ → Li₂CO₃ + H₂O
There are equal number of atoms of oxygen, hydrogen and lithium on both side of equation so it obey the law of conservation of mass.
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
2LiOH + CO₂ → Li₂CO₃ + H₂O
2(6.941 + 16 + 1) + 12+32 6.941×2 + 12 + 3×16 + 18
47.882 + 44 13.882 +12+48 + 18
91.882 g 91.882 g
The mass of reactants and product are equal.
The amount of matter in an object is its Mass...
Answer:
When the sun, moon, and Earth are in alignment (at the time of the new or full moon), the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides—both commonly called spring tides.
Answer:
(C) im pretty sure is the answer
Explanation:
