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umka21 [38]
3 years ago
14

What type of boundary exists around the Pacific Ocean?

Chemistry
1 answer:
Otrada [13]3 years ago
4 0

ιт ιѕ ¢αℓℓє∂ тнє ρα¢ιfι¢ ρℓαтє. ιт ιѕ α σ¢єαиι¢ тє¢σиι¢ ρℓαтє, ιт ℓιєѕ вєиєαтg тgє ρα¢ιfι¢ σ¢єαи

нσρє ι ¢συℓ∂ нєℓρ уσυ συт.

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If you have a 1500 g aluminum pot, how much heat energy is needed to raise its temperature by 100°C?
Nataly [62]

The heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ.

The heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.

Explanation:

The heat energy required to raise the temperature of any body can be obtained from the specific heat formula. As this formula states that the heat energy required to raise the temperature of the body is directly proportional to the product of mass of the body, specific heat capacity of the material and temperature change experienced by the material.

So in this problem, the mass of the aluminium is given as m = 1500 g, the specific heat of the aluminium is 0.900 J/g °C. Then as it is stated that the temperature is raised by 100 °C, so the pots are heat to increase by 100 °C from its initial temperature. This means the difference in temperature will be 100°C (ΔT = 100°C).

Then, the heat energy required to raise the temperature will be

q = m*c*del T = 1500 * 0.900 * 100 = 135000 = 135 kJ

Thus, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100 °C is 135 kJ.

Similarly, the mass of copper pot is given as 1500 g, the specific heat capacity of copper is 0.385 and the difference in temperature is 100  °C.

Then, the heat energy required to raise its temperature will be

q = m*c*del T = 1500 * 0.385 * 100 = 57750 = 57.75 kJ

And the heat energy required to raise the temperature of 1500 g of copper pot by 100°C is 57.75 kJ.

So, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ. And the heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.

8 0
3 years ago
Determine the molar mass of a compound that has a density of 0.1633 g/L at STP.<br> (show work)
hodyreva [135]

Answer:

                     M.Mass  =  3.66 g/mol

Data Given:

                  M.Mass  =  M = ??

                  Density  =  d  =  0.1633 g/L

                  Temperature  =  T  =  273.15 K (Standard)

                  Pressure  =  P  =  1 atm (standard)

Solution:

              Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.

                                             P V = n R T    ---- (1)

Also, we know that;

                       Moles  =  n  =  mass / M.Mass

Or,                                   n  =  m / M

Substituting n in Eq. 1.

                                             P V = m/M R T   --- (2)

Rearranging Eq.2 i.e.

                                             P M = m/V R T   --- (3)

As,

                     Mass / Volume = m/V = Density = d

So, Eq. 3 can be written as,

                                             P M = d R T

Solving for M.Mass i.e.

                                             M = d R T / P

Putting values,

M  =  0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm

M  =  3.66 g/mol

6 0
2 years ago
Why do adults have stem cells
Eva8 [605]

Adults have stem cells because they are needed to repair certain tissues in the body such as in the muscles, bone marrow, skin, teeth, heart, and liver, to name a few. Thus, they can develop into many different cell types and function to replace older and damaged tissues.

3 0
3 years ago
Read 2 more answers
What is the new volume of a balloon originally at 755 torr and 5.00 l is placed in a container in which the pressure is increase
Luba_88 [7]

Answer is: volume will be 3.97 liters.

Boyle's Law: the pressure volume law -  volume of a given amount of gas held  varies inversely with the applied pressure when the temperature and mass are constant.

p₁V₁ = p₂V₂.

p₁ = 755 torr.

V₁ = 5.00 l.

p₂ = 1.25 atm · 760 torr/atm.

p₂ = 950 torr.

755 torr · 5 l = 950 torr · V₂.

V₂ = 755 torr · 5 l / 950 torr.

V₂ =  3.97 l.

When pressure goes up, volume goes down.

When volume goes up, pressure goes down.

3 0
3 years ago
Read 2 more answers
What is the term for a fine grained soil deposited by the wind
balandron [24]

I think it is called a loess. Please correct me if I am wrong.

4 0
3 years ago
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