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3 years ago

Answer this FAST PLEASE IT WILL HELP ALOT AND THEIR IS 15 POINTS AND ILL GIVE BRAINLIEST!!

Chemistry

2 answers:

amm18123 years ago

8 0

Answer:

Explanation:

As fertilizer can run off into the reservoir and contaminate it with harmful chemicals

kolbaska11 [484]3 years ago

3 0

Answer:

Hey!

THE ANSWER IS C!

Explanation:

Excessive use of Fertilizers can have adverse effects on the water quality because it contains Nitrates, which are harmful for both Humans (if they drink the polluted water) and Aquatic Life (they cannot stand Nitrates so the excrete them instead)

HOPE THIS HELPS!!

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Explain how astronomers use spectrographs to identify the composition of a star.

Gwar [14]

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4 0

3 years ago

23°C = ______ K<br><br> -250<br> 296<br> 123<br> 23

strojnjashka [21]

Answer:

296

Explanation:

6 0

3 years ago

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Mazyrski [523]

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3 years ago

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photoshop1234 [79]

I think it could be C maybeee though

6 0

3 years ago

A site in Pennsylvania receives a total annual deposition of 2.688 g/mof sulfate from fertilizer and acid rain. The ratio by mas

sertanlavr [38]

According to the statement

2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid

<h3>What is neutralization?</h3>

A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization or neutralization. In a water reaction, neutralization ensures that there is no excess of hydrogen or hydroxide ions in the solution.

<h3>According to the given information:</h3>

The equation of the neutralization reaction between H2SO4 and CaCO3.

CaCO3 + H2SO4 → CaSO4 + H2CO3

H2CO3 dissociate to water and carbon dioxide.

CaCO3 + H2SO4 → CaSO4 + H2O + CO2

Now solving for the mass of CaCO3 needed to neutralize the acid.

mass of CaCO3 = 9460 Kg H2SO4 × $\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}} \times \frac{1 \mathrm{~mol} \mathrm{H}_2 \mathrm{SO} 4}{98.1 \mathrm{gH}_2 \mathrm{SO}_4} \times \frac{1 \mathrm{~mol} \mathrm{CaCO}\left(\mathrm{O}_3\right.}{1 \mathrm{~mol} \mathrm{H}_2 \mathrm{SO}_4}$ $\times \frac{100.1 \mathrm{~g} \mathrm{CaCO}_3}{1 \mathrm{~mol} \mathrm{CaCO}_3} \times \frac{2.205 \mathrm{lb}}{1000 \mathrm{~g}}$

= 21284.56606

mass of CaCO3 = 2.12 x 10^4 lbs

2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid.

To know more about neutralization visit:

brainly.com/question/12498769

#SPJ4

4 0

2 years ago