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3 years ago

__________ is an intermediate electron acceptor for oxidations that occur in both glycolysis and in krebs cycle reactions

Chemistry

1 answer:

Gnesinka [82]3 years ago

3 0

Answer: NADH

Explanation:

In both of the processes the electron acceptor is NADH which accepts the electrons. Glycolysis takes place in the cytoplasm of the cell.

In case of glycolysis the NADH accepts the electrons when the Glyceraldehydyde 3-phosphate is converted into 1, 3 Biphosphoglyceric acid. In the last step of the glycolysis 4 ATP molecules are produced.

Kreb's Cycle takes place in the mitochondria of the cell. During this process the electron acceptor is NADH. 3 molecules of NADH is produced during the process of citric acid cycle.

During the step when the isocitrate is converted into alphaketogluterate , alphaketogluterate is converted into succinyl co A and malate to oxaloacetate produces 1 molecules of NADH at each step.

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For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a

Volgvan

For this reaction, oxidation number of Carbon in CO would be +2 while oxidation number of carbon in CO2 would be +4 and so this means that carbon has oxidized. Oxidation number of nitrogen in NO is +2. While oxidation number of nitrogen in N2 is 0 so this means that nitrogen had reduced. The reducing agent is the one which provides electrons by oxidizing itself so in this case; CO is the reducing agent while the C in CO oxidized to produce electrons. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

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3 years ago

The ratio of sizes between the ionic radii of anions and cations in a cell has no influence on the manner of packing for that ce

Morgarella [4.7K]

Answer:

The answer is B. False

Explanation:

The ratio of sizes between the ionic radii of cations and anions in a cell influences the manner of packing for that cell thereby predicting the possible cation/anion coordination number in any compound and establishing the structure of ionic solids.

5 0

4 years ago

Where would a primary producer be located in a food chain?

vfiekz [6]

Answer:

The primary producer would be at the bottom of the food chain.

Explanation:

4 0

4 years ago

Read 2 more answers

How many moles of hydrogen are in 3. 06 × 10⁻³ g of glycine , c₂h₅no₂?.

Gala2k [10]

Answer:

n = 6.06 x $10^{-4}$ mol

Explanation:

n =?

m = 3.06 x 10-³ g

M (H5) = 5 x 1.01 (Since we only want hydrogen)

Atomic mass of C = 12.01

Atomic mass of H is 1,01, etc.

Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.

M = $\frac{m}{n}$ ⇔ n = $\frac{m}{M}$ ⇔ n = $\frac{3.06 x 10^{-3} }{5,05}$ ⇔ n = 6.06 x $10^{-4}$ mol

Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.

8 0

2 years ago

a sample of ammonia liberates 5.66 kj of heat as it solidifies at its melting point . what is the mass of the sample?

Reil [10]

The correct answer for the question that is being presented above is this one: "16.728 g."

Given that
ΔHsolid = -5.66 kJ/mol.
This means that 5.66 kJ of heat is released when 1 mole of NH3 solidifies

When 5.57 kJ of heat is released
amount of NH3 solidifies = 5.57/5.66 = 0.984 moles

molar mass of NH3 = 17 g/mole 
1 mole of NH3 = 17 g 
So, 0.984 moles of NH3 = 17 X 0.984 = 16.728 g

7 0

3 years ago