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3 years ago

Convert 32.56 km/hr into ft/hr

1 answer:

8 0

Note that
1 m = 3.2808 ft

Therefore
1 km = 3280.8 ft
and
$32.56 \, \frac{km}{h} = (32.56 \, \frac{km}{h})*(3280.8 \, \frac{ft}{km}) = 1.0682 \, \times 10^{5} \, \frac{ft}{h}$

Answer: 1.0682 x 10⁵ ft/hr

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Carbon-14 is a radioactive isotope that decays according to first-order kinetics in a process that has a half-life of 5730 years

Sliva [168]

Answer : The time passed in years is $2.83\times 10^3\text{ years}$

Explanation :

Half-life = 5730 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5730\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = ?

a = let initial amount of the reactant = X g

a - x = amount left after decay process = $71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg$

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}$

$t=2831.00\text{ years}=2.83\times 10^3\text{ years}$

Therefore, the time passed in years is $2.83\times 10^3\text{ years}$

8 0

3 years ago

Explain the main concept behind the VSEPR theory of molecular shape. How do both number and type of electron pairs influence the

vazorg [7]

According to the VSEPR hypothesis, each atom in a molecule will develop a shape that reduces the repulsion between its valence shell electrons.

<h3>What is the basis of VSEPR theory?</h3>

According to the valence-shell electron pair repulsion model, or VSEPR model, a molecule will modify its structure to maintain the greatest feasible distance between the valence electron pairs (based on the repulsive behavior of electron pairs). Given that negatively charged electrons repel one another, this makes sense.

<h3>How do both the number and type of electron pairs influence the shape of a molecule?</h3>

Electron pairings resemble groups of individuals who don't get along. They "like" to keep a safe distance between one another. Because carbon has only two electron domains, the molecular geometry of carbon dioxide is linear.

They consequently position themselves in the molecule as far apart as they can. This is how the molecule geometry is influenced by the number of electron domains.

Sulfur tetrafluoride is a trigonal bipyramidal molecule with four bonded and one non-bonding electron pair, or domain. The "shared" region between the two atoms is where the electrons in a covalent bond are most likely to be located. They become high electron density, compact zones as a result.

On the other hand, non-bonding electrons in a molecule's electron cloud are more "free" to "spread out." As a result, they are less dense and occupy a greater volume than bonding domains.

Therefore, what affects the geometry in a molecule is the "size" of a domain and the "desire" for electrons to be as far apart as feasible.

Learn more about VSEPR theory here:

brainly.com/question/10271048

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7 0

2 years ago

Why should the units in the ideal gas law be homogeneous when calculating R?

azamat

Answer: a

Explanation:

8 0

3 years ago

Read 2 more answers

Which of the following is equal to the number of particles in 18 grams of carbon-12

mote1985 [20]

Answer:

1.5 moles

Explanation:

Given data:

Mass of Carbon = 18 g

Number of particles = ?

Number of moles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 18 g carbon:

18 g / 12 g/mol = number of moles

1.5 moles

1.5 × 6.022 × 10²³ particles

9.03 × 10²³ particles

6 0

4 years ago

there are 3.0 x 10^22 molecules of sucrose in a sample. how many grams of sucrose is this? The molar mass of C12H22O11 is about

gladu [14]

The amount of sucrose in the sample would be 17 grams

<h3>Number of molecules of substances</h3>

There are 6.022 x $10^{23}$ molecules in 1 mole of every substance.

3.0 x $10^2^2$ molecules will, therefore, be:

1 x 3.0 x $10^2^2$ /6.022 x $10^{23}$ = 0.0498 moles

Mass of 0.0498 moles sucrose = 0.0498 x 342 = 17 grams

More on the number of molecules of substances can be found here: brainly.com/question/19481036

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5 0

2 years ago