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ololo11 [35]
3 years ago
13

If the average speed of an orbiting space shuttle is 27 800 km/h, determine the time required for it to circle Earth. Assume tha

t the shuttle is orbiting about 320.0 km above Earthâs surface, and that Earthâs radius is 6380 km.
Physics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

 t = 1.51 hours

Explanation:

given,

Speed of space shuttle. v = 27800 Km/h

Radius of earth, R = 6380 Km

height of shuttle above earth, h = 320 Km

Total radius of the shuttle orbit

r' = R + h

r' = 6380 + 320

r' = 6700 Km

distance, d = 2 π r

   d = 2 π x 6700

time = \dfrac{distance}{speed}

time = \dfrac{2\pi\times 6700}{27800}

 t = 1.51 hours

Time require by the shuttle to circle the earth is equal to 1.51 hr.

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<h3>Convection current</h3>

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2 years ago
A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is
Luden [163]

The period will be the same if the amplitude of the motion is increased to 2a

What is an Amplitude?

Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

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We know that,

The time period for the spring is calculated with the equation:

T = 2\pi \sqrt{\frac{m}{k} }

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Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

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7 0
2 years ago
Describe a vector and how it is used​
Ilia_Sergeevich [38]

Answer:

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Explanation:

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8 0
3 years ago
If the area of an iron rod is 10 cm by 0.5 cm and length is 35 cm. Find the value of resistance, if 11x10^-8 ohm.m be the resist
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Answer:

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Explanation:

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We need to find the resistance of the iron rod. It is given by :

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R=11\times 10^{-8}\times \dfrac{0.35\ m}{0.0005\ m^2}

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Explanation:

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5 0
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