If the average speed of an orbiting space shuttle is 27 800 km/h, determine the time required for it to circle Earth. Assume tha
1 answer:
Answer:
t = 1.51 hours
Explanation:
given,
Speed of space shuttle. v = 27800 Km/h
Radius of earth, R = 6380 Km
height of shuttle above earth, h = 320 Km
Total radius of the shuttle orbit
r' = R + h
r' = 6380 + 320
r' = 6700 Km
distance, d = 2 π r
d = 2 π x 6700
t = 1.51 hours
Time require by the shuttle to circle the earth is equal to 1.51 hr.
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Answer:
a) 20 seconds
b) No.
Explanation:
t = Time taken for jet to stop
u = Initial velocity = 100 m/s (given in the question)
v = Final velocity = 0 (because the jet will stop at the end)
s = Displacement of the jet (Distance between the moment the jet touches the ground to the point the point it stops)
a = Acceleration = -5.00 m/s² (slowing down, so it is negative)
a) Equation of motion
The time required for the plane to slow down from the moment it touches the ground is 20 seconds.
The distance it requires for the jet to stop is 1000 m so in a small tropical island airport where the runway is 0.800 km long the plane would not be able to land. The runway needs to be atleast 1000 m long here the runway on the island is 1000-800 = 200 m short.