If the average speed of an orbiting space shuttle is 27 800 km/h, determine the time required for it to circle Earth. Assume tha
1 answer:
Answer:
t = 1.51 hours
Explanation:
given,
Speed of space shuttle. v = 27800 Km/h
Radius of earth, R = 6380 Km
height of shuttle above earth, h = 320 Km
Total radius of the shuttle orbit
r' = R + h
r' = 6380 + 320
r' = 6700 Km
distance, d = 2 π r
d = 2 π x 6700
t = 1.51 hours
Time require by the shuttle to circle the earth is equal to 1.51 hr.
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Answer:
The answer to the question is as follows
The acceleration due to gravity for low for orbit is 9.231 m/s²
Explanation:
The gravitational force is given as
Where = Gravitational force
G = Gravitational constant = 6.67×10⁻¹¹
m₁ = mEarth = mass of Earth = 6×10²⁴ kg
m₂ = The other mass which is acted upon by and = 1 kg
rEarth = The distance between the two masses = 6.40 x 10⁶ m
therefore at a height of 400 km above the erth we have
r = 400 + rEarth = 400 + 6.40 x 10⁶ m = 6.80 x 10⁶ m
and =
= 9.231 N
Therefore the acceleration due to gravity = /mass
9.231/1 or 9.231 m/s²
Therefore the acceleration due to gravity at 400 kn above the Earth's surface is 9.231 m/s²