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Paul [167]
3 years ago
11

Can someone help me please

Chemistry
1 answer:
zhuklara [117]3 years ago
8 0

Answer:

unicellular means having one cell and multicellular means having many cell

example of unicellular organism are euglena,amoeba and paramecium

example of multicellular are man,mushroom and

dog

Explanation:

hope it helps you

You might be interested in
How many grams of methanol is formed by the mild oxidation of 64 grams of methane?
Dafna1 [17]

Answer: 1. Introduction

ARTICLE SECTIONSJump To

Currently, there exists no industrial process capable of directly converting methane to methanol. While many processes have been explored, none to date has proven cost-effective. A consequence of the paucity of catalysts for the direct oxidation of methane to methanol is the annual flaring of 140 billion cubic meters of natural gas at remote oil drilling locations around the world, accounting for 1% of global CO2 emissions with no associated energy gains.(1) Two distinct problems are often cited as being responsible for the lack of catalysts available for such a process: the large barriers associated with activating the nonpolar and highly symmetric methane molecule and the higher relative reactivity of the desired products.(2,3) Regarding the first problem, while methane activation barriers on transition metals are generally high (ΔGa(300 K, 1 bar) > 1.2 eV),(4) several publications have highlighted nontransition metal catalysts able to activate methane at low temperatures or with low density functional theory (DFT)-predicted barriers.(5−8) However, solutions to the second problem, that of product reactivity, have proven more elusive. Even if methanol can be locally produced by a catalyst at low temperatures, it is difficult to stop its CH bonds, which have a 0.4 eV lower bond dissociation energy (BDE) than those in methane, from being further oxidized.(3,9) Indeed, an example of a continuous process able to simultaneously achieve both high methane conversion and high methanol selectivity has yet to be established, pointing to a robust selectivity–conversion trade-off.(10)

In light of this challenge, many efforts have shifted focus from catalytic to stepwise processes, in which reactant consumption and product collection are decoupled. These systems bypass the aforementioned selectivity–conversion trade-off by producing a protected methanol derivative that is less prone to further oxidation compared to free methanol. Examples in homogeneous catalysis are often quasi-catalytic, i.e., turnover number (TON) > 1, and proceed through the use of small-molecule protecting groups. For example, Periana et al. oxidized methane to a stable methyl bisulfate product that could later be hydrolyzed to yield methanol and sulfuric acid.(11,12) However, these systems are limited by expensive oxidants and the cost of recycling protecting groups. Similarly, it was found that metal-exchanged zeolites, which had previously achieved methanol yields of ∼3% (64% CH3OH selectivity; 5% CH4 conversion) in the catalytic process,(13) could unlock higher methanol selectivities (∼98%) when used as heterogeneous protecting groups to oxidize methane to methanol stoichiometrically (TON = 1).(14−18) Such processes typically involve three steps: zeolite activation at high temperatures (∼450 °C), stoichiometric methane oxidation at lower temperatures (∼150 °C), and methanol recovery by flowing water (∼150 °C).(15) Unfortunately, this energy-intensive temperature cycling in combination with the expensive oxidizing agents required to reactivate the catalyst and low methanol yields per cycle tend to limit the practical application of these approaches.(10)

Herein, we aim to understand the limitations of direct methane to  

Explanation: Sorry for how long it is

8 0
3 years ago
Based on the information given, classify each of the pure substances as elements or compounds, or indicate that no such classifi
Olenka [21]

Answer:

Analysis with an elaborate instrument indicates that:

  • <u>Substance A contains two elements. </u>

   

               Compound

  • <u>Substance B and substance C react to give a new substance D. </u>

              Insufficient information

  • <u>Substance E decomposes upon heating to give substance F and substance G. </u>

            Compound

  • <u>Heating substance H to 1000 °C causes no change. </u>

          Insufficient information

  • <u>Substance I cannot be broken down into simpler substances by chemical means. </u>

               Element

  • <u>Substance J cannot be broken down into simpler substances by physical means</u>

              Insufficient information

Explanation:

Important background:

  • <em>Pure substances </em>are elements or compounds.

  • <em>Elements</em> are formed by only one kind of atoms. They cannot be broken down into another substance by chemical or physical means. There are only 118 known elements; they are all listed in the periodic table.

  • <em>Compounds</em> have fixed chemical composition and are formed by two or more kind of atoms, chemically bonded. They can be broken down into different pure substances, either elements or other substances, only by chemical changes.

With tha information let's see every statement about the pure substances that should be classified as elements or compounds.

  • <u> Substance A contains two elements:</u> compound

   

               Since, the pure substance contains two elements, it is not just and element by a compound. This is because a compound is a pure substance composed of two or more elements.

  • <u>Substance B and substance C react to give a new substance D</u>.: Insufficient information

        Either two elements, one element and one compound, or two compounds may react to give a new substance, so you cannot assure what kind of pure substance B and C are.

For instance:

    - two elements like hydrogen and oxygen reacto to give water (a compound)

  - a compound like CH₂=CH₂ react with an element like Cl₂ to give CH₂Cl-CH₂Cl

  • <u>Substance E decomposes upon heating to give substance F and substance G.</u> : Compound

An element cannot be decomposed into two different substances, since the elements are composed by just one kind of atoms.

So, if the substance E decomposes into two different substances, F and G, E necessarily has to be a compound.

  • <u>Heating substance H to 1000 ∘C causes no change.</u> Insufficient information

The mere fact that a substance has not changed by heating at such extreme temperature cannot assure whether the substance is a compound or an element.

Some compounds are stable at very high temperatures. For instace, magnesium oxide, MgO, has a melting point of 2852°C, meaning that it will remain a a solid substance way beyond 1,000°C

  • <u>Substance I cannot be broken down into simpler substances by chemical means. </u>Element

Since an element is formed by one single kind of atoms, it cannot be broken down into simpler substances by chemical means; but a compose does, because it is formed by two or more different elements chemically bonded.

  • <u>Substance J cannot be broken down into simpler substances by physical means</u>: Insufficient information

The distintion between compounds and elements is based on chemical changes; the fact that physical changes do not change the substance does not tell anything about the fact that the substance is composed by one kind of elements or several elements chemical boonded.

Hence, physical means do not provide sufficient information to conclude about whether a substance is an element or a compound.

4 0
3 years ago
The combining of two atomic nuclei to produce one larger nucleus is called
Naddika [18.5K]
C.
Nuclear fission involves the high energy collision of two atomic nuclei to produce one larger nucleus; this process powers stars.
6 0
4 years ago
HELP!!!!! How much does a sample of Argon weigh if it occupies 25.4 L at a pressure of 2.45 atm and a temperature of 482 K?
Artist 52 [7]

Answer:

62.82 g

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of moles of argon, R = molar gas constant, T = Temperature.

But,

Number of mole (n) = mass (m)/molar mass(m')

n = m/m'................... Equation 2

Substitute equation 2 into equation 1

PV = (m/m')RT.............. Equation 3

From the question, we were asked to find m.

There make m the subject of formula in equation 3

m = PVm'/RT.............. Equation 4

Given: P = 2.45 atm, V = 25.4 L, T = 482 K

Constant: R = 0.082 atm.dm³.K⁻¹.mol⁻¹, m' = 39.9 g/mol

Substitute these values into equation 4

m = (2.45×25.4×39.9)/(0.082×482)

m = 62.82 g.

5 0
3 years ago
What is the silver concentration in a solution prepared by mixing 250
kotegsom [21]

Answer:

0.221M

Explanation:

From the question ,

The Molarity of AgNO₂ = 0.310 M

Hence , the concentration of Ag⁺ = 0.301 M

The volume of  AgNO₂  = 250 mL

and,

The Molarity of Sodium chromate = 0.160 M

The volume of Sodium chromate =  100 mL.

As the solution is mixed the final volume becomes ,

250mL +100mL = 350mL

Now, using the formula , to find the final molarity of the mixture ,

M₁V₁ ( initial ) =  M₂V₂ ( final )

substituting the values , in the above equation ,  

0.310M  *  250ml  =  M₂ * 350ml

M₂ = 0.221M

Hence , the concentration of the silver in the final solution = 0.221M

6 0
4 years ago
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