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natima [27]
4 years ago
7

A truck is traveling due north at 50 km/hr approaching a crossroad. On a perpendicular road a police car is traveling west towar

d the intersection at 45 km/hr. Both vehicles will reach the crossroad in exactly one hour. Find the vector currently representing the displacement of the truck with respect to the police car.
Physics
1 answer:
kirill [66]4 years ago
8 0

Answer:45\hat{i}+50\hat{j}

Explanation:

Truck velocity=50 km/hr

police car velocity =45 km/hr

Let they start at t=0 s

After one hour

truck displacement=50\times 1=50 km

In vector Form(r_1)=50\hat{j}

For Police car displacement=45\times 1=45 km

in vector form(r_2)=-45\hat{i}

r_{12}=50\hat{j}-(-45\hat{i})

r_{12}=45\hat{i}+50\hat{j}

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Compute the size of the charge necessary for two spheres separated by 1m to be attached with the force of 1N. How many electrons
yarga [219]

Answer:

q\approx 6.6\cdot 10^{13}~electrons

Explanation:

<u>Coulomb's Law</u>

The force between two charged particles of charges q1 and q2 separated by a distance d is given by the Coulomb's Law formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

We know both charges are identical, i.e. q1=q2=q. This reduces the formula to:

\displaystyle F=k\frac{q^2}{d^2}

Since we know the force F=1 N and the distance d=1 m, let's find the common charge of the spheres solving for q:

\displaystyle q=\sqrt{\frac{F}{k}}\cdot d

Substituting values:

\displaystyle q=\sqrt{\frac{1}{9\cdot 10^9}}\cdot 1

q = 1.05\cdot 10^{-5}~c

This charge corresponds to a number of electrons given by the elementary charge of the electron:

q_e=1.6 \cdot 10^{-19}~c

Thus, the charge of any of the spheres is:

\displaystyle q = \frac{1.05\cdot 10^{-5}~c}{1.6 \cdot 10^{-19}~c}

\mathbf{q\approx 6.6\cdot 10^{13}~electrons}

5 0
3 years ago
A boat produced water waves of frequency 4 Hz and wavelength 2m, if it reached the shore after 2 seconds how far is the boat fro
kap26 [50]

Answer:

S = 16 m

Explanation:

Given that

The frequency of the water waves, f = 4 Hz

The wavelength of the water waves, λ = 2 m

The time the waves reached the shore, t = 2 s

The relation between the velocity, wavelength, and the frequency of the wave is given by the relation,

                                           v = f λ    m/s

Substituting the given values in the above equation,

                                           v = 4 x 2

                                              = 8 m/s

The velocity of the water waves is v = 8 m/s

The distance between the shore and boat is given by

                                            s = v x t

                                               = 8 x 2

                                               = 16 m

Hence, the distance between the boat and the shore is, s = 16 m

7 0
3 years ago
I need help with nine and 10 I will really appreciate it
horsena [70]

Answer:

9] V = D ÷ T

Take any distance value from the graph and its relevant time.

V = 4 ÷ 2

V = 2 m/s

[You will notice that any distance values with its time will give you 2 m/s as its speed. This means that speed is constant throughout.]

10] Take the distance value and its time for the highest peak of B.

V = 20 ÷ 2

V = 10 m/s

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2 years ago
WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!
stepan [7]
*FRICTIONAL FORCE* in the opposite direction of the way Bobby is pushing.
Friction is a force which varies but it is always opposing the direction of motion.

*APPLIED FORCE* is the force that Bobby is pushing with.
An applied force is literally the force that is applied to an object.

*WEIGHT FORCE* is also called the force of gravity. It is straight downward.
It is the weight of the object multiplied by the force of gravity. If the TV weighed 100kg, acceleration is always 9.81 m/s^2, so the weight force would be 981 N.

*NORMAL FORCE* is the force which is holding the TV above ground. The ground supplies a force upward against the TV.
Normal force is just the force that prevents the TV from falling through the ground. We don't normally realize it in our everyday life, but the floor must hold everything up because gravity is always "pushing" against it.
3 0
3 years ago
I NEED HELP ASAP! PLSSSSSSSSSSSSSSSSSSS
OleMash [197]
I’m pretty sure

Part 1; C
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3 years ago
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