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Romashka [77]
3 years ago
5

6. A yo-yo with a mass of 0.5 kg is tied to a radius of 2 m and is spinning at 3 m/s. What

Physics
1 answer:
pshichka [43]3 years ago
6 0

Given that,

Mass of yo-yo, m = 0.5 kg

Radius of the path, r = 2 m

Speed of the object, v = 3 m/s

To find,

The centripetal force acting on the yo-yo.

Solution,

The formula for the centripetal force is given as follows :

F=\dfrac{mv^2}{r}\\\\F=\dfrac{0.5\times (3)^2}{2}\\\\F=2.25\ N

So, the magnitude of centripetal force acting on the y-yo is 2.25 N.

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What happens to the frequency of a wave If the wavelength is decreased by half
podryga [215]

Answer:

Frequency  doubles.

Explanation:

Frequency doubles because Wavelength and Frequency are inversely proportional. That means if one decreases the other one increases. So, if wavelength is half, frequency is the opposite, doubles.

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3 years ago
An 80 g, 40 cm long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 15 g ball of clay trav
fiasKO [112]

Answer:

θ  = 12.95º

Explanation:

For this exercise it is best to separate the process into two parts, one where they collide and another where the system moves altar the maximum height

Let's start by finding the speed of the bar plus clay ball system, using amount of momentum

The mass of the bar (M = 0.080 kg) and the mass of the clay ball (m = 0.015 kg) with speed (v₀ = 2.0 m / s)

Initial before the crash

      p₀ = m v₀

Final after the crash before starting the movement

     p_{f} = (m + M) v

     p₀ = p_{f}

     m v₀ = (m + M) v

     v = v₀ m / (m + M)

     v = 2.0 0.015 / (0.015 +0.080)

     v = 0.316 m / s

With this speed the clay plus bar system comes out, let's use the concept of conservation of mechanical energy

Lower

    Em₀ = K = ½ (m + M) v²

Higher

    E_{mf} = U = (m + M) g y

   Em₀ = E_{mf}

   ½ (m + M) v² = (m + M) g y

   y = ½ v² / g

   y = ½ 0.316² / 9.8

   y = 0.00509 m

Let's look for the angle the height from the pivot point is

    L = 0.40 / 2 = 0.20 cm

The distance that went up is

     y = L - L cos θ

     cos θ  = (L-y) / L

     θ  = cos⁻¹ (L-y) / L

     θ  = cos⁻¹-1 ((0.20 - 0.00509) /0.20)

      θ  = 12.95º

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