Answer:
5
Explanation:
NH4OH
The subscript gives the info that there are 4 hydrogen atoms but there is another H in the formula so you add them up.
Answer:
See below
Explanation:
Hello there!
Electronegativity is the atom's tendency to attract electrons in a chemical bond
There are two trends to electronegativity:
- Electronegativity increases from bottom to top in a group (Li has a greater electronegativity than Fr, for example)
- Electronegativity increases from left to right across a period (the further right the group, the greater the electronegativity)
Looking at a period table, Sb, Sn, Te, and I are all in the same period, so we'll need to decide which element has the highest electronegativity based on the group.
- Sn belongs to group 4A (group 14)
- Sb belongs to group 5A (group 15)
- Te belongs to group 6A (group 16)
- I belongs to group 7A (group 17)
As I belongs to group 7A, the group that is the farthest right based off of the options given, I has the highest electronegativity
Hope this helps!
The electron group arrangement of CH₂Cl₂ is penta-atomic. The molecular shape is tetrahedral, and the bond angle is 109.5°.
<h3>What is the bond angle?</h3>
The bond angle is the angle between the atoms of the compound. The bond angle is defined in degree. The bond length is also there. It is the distance between the nuclei of the two atoms.
The bond angle of CH₂Cl₂ is 109.5°. According to the VSEPR theory, as the structure will be tetrahedral.
Thus, the penta-atomic configuration of CH2Cl2's electrons. Tetrahedral is the molecular shape, the bond angle is 109.5°.
To learn more about bond angle, refer to the link:
brainly.com/question/14089750
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Answer:
[Ar] 3d10 4s1
Explanation:
The correct electronic configuration of copper is [Ar] 3d10 4s1
Copper has atomic number 29 and due to the stability of half filled or fully filled orbitals or shells, the electrons from the 4s jumps to the 3d and makes the 3d shell contain 10 electrons.
This is what I mean:
Cu = Ar 4s2 3d10 is the expected configuration of copper when we follow the principle of filling the various orbitals that is the s, p, d, f orbitals.
But because we write 3d before writing 4s, we have Ar 3d10 4s2. Instead of this configuration becoming the correct one, an electron from the 4s orbital jumps to the 3d orbital to complete the orbital giving the electrons in the 3d orbital 10.
So therefore the correct configuration is Ar 3d10 4s1
It is because precise amount measured is required for the reaction to take place chemically, and an accurate conclusion will prevent any dangerous and misleading conclusions made due to inaccurate data.
For example, in physics, every measurement we state the instrument uncertainty after the measurement, stating that it is not a definite certain measurement, but the smaller the value for the uncertainty, the more precise that instrument's data is.
Precise is important in terms of knowing how many moles or grams of reactant is required for this reaction to complete without any shortage or excess chemically. Accuracy is based on the conclusions we make in regards to the data and observations we make experimentally.
