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riadik2000 [5.3K]
4 years ago
12

Which carbonyl compounds do not undergo an aldol reaction when treated with −oh in h2o? select all that apply?

Chemistry
1 answer:
GREYUIT [131]4 years ago
6 0
Answers:
              Among many few compounds are shown below which can not undergo Aldol Condensation reactions.

Explanation:
                   Aldol Condensation reactions are given by those carbonyl compounds which are capable of forming conjugate bases called as Enolates. Enolates are formed when carbonyl compounds having hydrogen atoms at alpha position are treated with strong bases. This hydrogen atom at alpha position is mildly acidic in nature and readily donated to base as the upcoming conjugate base i.e. has stability due to resonance. 
                  So those carbonyl compounds which lacks these acidic protons at alpha position are not able to form enolates, Hence, unable to undergo Aldol Condensation reactions. Few examples are attached below,

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How many moles are in 5.4x1024 molecules of C4H2F7I, heptafluoro-1-iodobutane? Group of answer choices
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Given :

Number of molecules of C_4H_2F_7I.

To Find :

How many moles are in given number of molecules.

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We know, in 1 moles of any element/compound contains 6.022\times 10^{23} at atoms/molecules.

So, number of moles in 5.4\times 10^{24} molecules are :

n = \dfrac{5.4\times 10^{24}}{6.022\times 10^{23}}\\\\n = 8.97 \ moles

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3 years ago
Will these changes increase, decrease, or have no effect on the mean free path of the molecules in a gas sample?
lisabon 2012 [21]
According to the kinetic theory, the mean free path is the average distance a single atom or molecule of an element or compound travels with respect with the other atoms during a collision. The greater the mean free path, the more ideal the behavior of a gas molecule is because intermolecular forces are minimum. To understand which factors affect the mean free path, the equation is written below.

l = μ/P * √(πkT/2m), where
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P is the pressure
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m is the molar mass

So, here are the general effects of the factors on the mean free path:

Mean free path increases when:
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6 0
4 years ago
Determine the volume of carbon dioxide gas produced at STP when 2.5 g of nitroglycerin decomposes by this balanced equation. 4C3
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Answer:

0.67 L

Explanation:

Given data:

Volume of carbon dioxide = ?

Mass of nitroglycerine = 2.5 g

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Solution:

Chemical equation:

4C₃H₅N₃O₉    →    12CO₂ + 10 H₂O + 6N₂ + O₂

Number of moles of nitroglycerine:

Number of moles = mass/ molar mass

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Number of moles = 0.01 mol

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             C₃H₅N₃O₉          :         CO₂

                 4                     :           12

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PV = nRT

V = nRT/P

V = 0.03 mol×  0.0821 atm.L/mol.K× 273.15 K / 1 atm

V = 0.67 L

4 0
3 years ago
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