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riadik2000 [5.3K]
3 years ago
12

Which carbonyl compounds do not undergo an aldol reaction when treated with −oh in h2o? select all that apply?

Chemistry
1 answer:
GREYUIT [131]3 years ago
6 0
Answers:
              Among many few compounds are shown below which can not undergo Aldol Condensation reactions.

Explanation:
                   Aldol Condensation reactions are given by those carbonyl compounds which are capable of forming conjugate bases called as Enolates. Enolates are formed when carbonyl compounds having hydrogen atoms at alpha position are treated with strong bases. This hydrogen atom at alpha position is mildly acidic in nature and readily donated to base as the upcoming conjugate base i.e. has stability due to resonance. 
                  So those carbonyl compounds which lacks these acidic protons at alpha position are not able to form enolates, Hence, unable to undergo Aldol Condensation reactions. Few examples are attached below,

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ladessa [460]
Answer is: carbon.

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7 0
3 years ago
Read 2 more answers
Caffeine (C8H10N4O2) is a stimulant found in coffees and teas. When dissolved in water, it can accept a proton from a water mole
Olenka [21]

Answer:

See figure 1

Explanation:

If we want to find the acid and the Brønsted-Lowry base, we must remember the definition for each of these molecules:

-) Acid: hydrogen donor

-) Base: hydrogen acceptor

In the <u>caffeine structure,</u> we have several atoms of nitrogen. These nitrogen atoms have the ability to <u>accept</u> hydronium ions (H^+). Therefore the caffeine molecule will be the base since it can accept

If caffeine is the base, the water must be the acid. So, the water in this reaction donated a hydronium ion.

<u>Thus, caffeine is the base and water the acid. (See figure 1)</u>

3 0
3 years ago
23492u undergoes alpha decay. what is the atomic number of the resulting element.
mash [69]
Alpha decay involves the loss of an alpha particle, aka a helium nucleus. This results in the mass number of the original element decreasing by 4 and the atomic number decreasing by 2. Assuming 23942u is uranium (92), the resulting element's atomic number is 90, making it thorium.
4 0
2 years ago
The pKb of the base cyclohexamine, C6H11NH2, is 3.36. What is the pKa of the conjugate acid, C6H11NH3
bonufazy [111]

Answer:

10.64

Explanation:

Let's consider the basic reaction of cyclohexamine, C₆H₁₁NH₂.

C₆H₁₁NH₂(aq) + H₂O(l) ⇄ C₆H₁₁NH₃⁺(aq) + OH⁻     pKb = 3.36

C₆H₁₁NH₃⁺ is its conjugate acid, since it donates H⁺ to form C₆H₁₁NH₂. C₆H₁₁NH₃⁺ acid reaction is as follows:

C₆H₁₁NH₃⁺(aq) + H₂O(l) ⇄ C₆H₁₁NH₂(aq) + H₃O⁺(aq)   pKa

We can find the pKa of C₆H₁₁NH₃⁺ using the following expression.

pKa + pKb = 14.00

pKa = 14.00 - pKb = 14.00 - 3.36 = 10.64

6 0
3 years ago
The half-life of tritium, or hydrogen-3, is 12.32 years. After about 37 years, how much of a sample of tritium will remain uncha
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1/16 ( ignore this the stupid website just makes us use 20 characters UGH! )
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