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Karolina [17]
3 years ago
11

How would YOU define speed?

Physics
2 answers:
mamaluj [8]3 years ago
7 0

Answer:

Speed is a way of measuring how quickly something is moving or being done, or something moving fast. An example of speed is a car being driven 45 miles per hour. An example of speed is someone cleaning a room in 10 minutes.

bija089 [108]3 years ago
3 0
Speed is a scalar quantity that refers to “how fast an object is moving.”
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bezimeni [28]

4.Use Ohm’s Law to determine the resistance in a circuit if the voltage is 12.0 volts and the current is 4.0 amps.

A. 8.0 ohms B. 48 ohms C. 3.0 ohms D. 12 ohms

Ohm's law is V=IR, or I=V/R, or R=V/I. (I= current, V= voltage, R= resistance.) Let's plug in our variables: V=12.0, I=4.0, R=? into the equation R=V/I. 12.0/4.0=3.0, so the resistance is 3.0 ohms.

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3 years ago
A substance has a half-life of 10,000 years and an initial mass of 1,000 grams. How many years will pass before only 250 grams o
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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ After 10,000 years the mass will be:

1,000 / 2 = 500

After 20,000 years the mass will be:

500/2 = 250

As you can see, the correct answer would be A. 20,000 years

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Who was the last person to step on the moon?
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Eugene Cernan was not the last, but he was the most recent.
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) Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) . What are (a)
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To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.

The vector product between the Force and the radius allows us to obtain the torque, in this way,

\tau = \vec{F} \times \vec{r}

\tau = (8i+6j)\times(-3i+4j)

\tau = (8*4)(i\times j)+(6*-3)(j\times i)

\tau = 32k +18k

\tau = 50 k

Therefore the torque on the particle about the origen is 50k

PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,

cos\theta = \frac{r\cdot F}{|\vec{r}|*|\vec{F}|}

cos\theta = \frac{(8*-3)+(4*3)}{\sqrt{(-3)^2+4^2}*\sqrt{8^2+6^2}}

cos\theta = -0.24

\theta = cos^{-1} (-0.24)

\theta = 103.88\°

Therefore the angle between the ratio and the force is 103.88°

5 0
2 years ago
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