All categories

4 years ago

When does fertilization take place

Physics

1 answer:

lutik1710 [3]4 years ago

6 0

IN HUMANS -

Since ovulation usually occurs around 14 days after the first day of your period, fertilization usually takes place in “week 3” of pregnancy. So, for the first two weeks of the gestational period, you're not actually pregnant at all.

IN PLANTS -

Fertilization takes part in the ovary of a female flower. Wind or pollinators carry the pollen from the male anthers to the female flower parts. After the pollen lands on the stigma, a pollen tube forms, and male reproductive material travels down the style and into the ovary, where it fertilizes an ovule.

You might be interested in

Cosmic inflation refers to ____(A) the current period of cosmic acceleration.(B) stellar winds creating bubbles of gas.(C) the U

Brilliant_brown [7]

Answer:

(D) a brief early period of hyper rapid expansion of space-time.

Explanation:

Cosmic inflation is a theory which states that in an interval of 10⁻³⁶ seconds to around 10⁻³³ seconds after the big bang there was a massive expansion.

According to the big bang theory the universe came to be from a singularity i.e., a point of infinite gravitational field. The universe is expanding this means that according to the conservation of energy the universe was expanding from the beginning.

8 0

3 years ago

In a laboratory, you determine that the density of a certain solid is 5.23× 10 −6 kg/m m 3 . convert this density into kilograms

tamaranim1 [39]

Density is given as

$\rho = 5.23 * 10^{-6} kg/mm^3$

now we have to convert this density into $kg/m^3$

now we have

$1 m = 1000 mm$

$\rho = 5.23 * 10^{-6} \frac{kg}{(1*10^-3 m)^3}$

$\rho = 5.23 * 10^{-6} \frac{1*10^9 kg}{m^3}$

$\rho = 5.23 * 10^3 kg/m^3$

$\rho = 5230 kg/m^3$

8 0

3 years ago

The range of all electromagnetic radiation is known as the

Readme [11.4K]

B.) <span>The range of all electromagnetic radiation is known as the "Electromagnetic Spectrum"

Hope this helps!
</span>

6 0

3 years ago

Discuss the formation of thunderstorms and tornadoes

mestny [16]

There diffrent but can cause the same thing

6 0

3 years ago

What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s 2 ) towards the Eart

Wittaler [7]

Answer:

The centripetal acceleration as a multiple of $g=9.8 m/s^{2}$ is $1.020x10^{-3}m/s^{2}$

Explanation:

The centripetal acceleration is defined as:

$a = \frac{v^{2}}{r}$ (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

$v = \frac{2 \pi r}{T}$ (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude $71.9^{\circ}$ . Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

$\cos \theta = \frac{adjacent}{hypotenuse}$

$\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}}$ (3)

Where $r_{71.9^{\circ}}$ is the radius at the latitude of $71.9^{\circ}$ and $r_{e}$ is the radius at the equator ( $6.37x10^{6}m$ ).

$r_{71.9^{\circ}}$ can be isolated from equation 3:

$r_{71.9^{\circ}} = r_{e} \cos \theta$ (4)

$r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})$

$r_{71.9^{\circ}} = 1.97x10^{6} m$

Then, equation 2 can be used

$v = \frac{2 \pi (1.97x10^{6} m)}{24h}$

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

$T = 24h . \frac{3600s}{1h}$ ⇒ $84600s$