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goblinko [34]
3 years ago
5

Which region of a longitudinal wave is this?

Physics
1 answer:
ipn [44]3 years ago
8 0
I think the correct answer is is D.
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Bedrock that is closer to oceanic ridges is younger in age than bedrock that is farther away. What can best be concluded from th
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The shape of Earth's lithosphere is continually changing. Bedrock that is closer to oceanic ridges is younger in age than bedrock that is farther away. What can best be concluded from this information? It can cause pollution of water in lakes and rivers
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5. Kelvin applied a rightward force of 302 N to a 29 kg desk to accelerate it across the floor. The
Naddik [55]

The force of friction is 213.2 N

Explanation:

The frictional force acting on an object sliding on a surface is given by:

F_f = \mu mg

where:

\mu is the coefficient of friction

m is the mass of the object

g is the acceleration of gravity

In this problem we have

\mu=0.750

m = 29 kg

g=9.8 m/s^2

Therefore, the force of friction is

F_f = (0.750)(29)(9.8)=213.2 N

Learn more about friction:

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3 years ago
What are the blue or red big dancing thing infront of a car wash called thank you
Alenkinab [10]
it’s called a tube man
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3 years ago
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How to calculate kinetic energy given mass and velocity
sashaice [31]

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

3 0
2 years ago
A mass weighting 16 lbs stretches a spring 3 inches. The mass is in a medium that exerts a viscous resistance of 20 lbs when the
const2013 [10]

Answer:

The equation for the object's displacement is u(t)=0.583cos11.35t

Explanation:

Given:

m = 16 lb

δ = 3 in

The stiffness is:

k=\frac{m}{\delta } =\frac{16}{3} =5.33lb/in

The angular speed is:

w=\sqrt{\frac{k}{m} } =\sqrt{\frac{5.33*386.4}{16} } =11.35rad/s

The damping force is:

F_{D} =cu

Where

FD = 20 lb

u = 4 ft/s = 48 in/s

Replacing:

c=\frac{F_{D} }{u} =\frac{20}{48} =0.42lbs/in

The critical damping is equal:

c_{c} =\frac{2k}{w} =\frac{2*5.33}{11.35} =0.94lbs/in

Like cc>c the system is undamped

The equilibrium expression is:

u(t)=u(o)coswt+u'(o)sinwt\\u(o)=7=0.583\\u'(o)=0\\u(t)=0.583coswt\\u(t)=0.583cos11.35t

3 0
3 years ago
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