<span>from a trough to the rest position and from a crest to the rest position.
</span>
Answer:
A) 1.88 * 10^17 m
B) 1.22 * 10^34 J
C) 1.95 * 10^34 J
Explanation:
Parameters given:
Mass of planet = 7.00 * 10^25 kg
Radius of orbit = 6.00 * 10^11 m
Force exerted on planet = 6.51 * 10^22 N
Velocity of planet = 2.36 * 10^4 m/s
A) The distance traveled by the planet is half of the circumference of the orbit (which is circular).
The circumference of the orbit is
C = 2 * pi * R
R = radius of orbit
C = 2 * 3.142 * 6.0 * 10¹¹
C = 3.77 * 10¹² m
Hence, distance traveled will be:
D = 0.5 * 3.77 * 10¹²
D = 1.88 * 10 ¹² m/s
B) Work done is given as:
W = F * D
W = 652 * 10²² * 1.88 * 10¹¹
W = 1.22 * 10³⁴ J
C) Change in Kinetic energy is given as:
K. E. = 0.5 * m * v²
K. E. = 0.5 * 7 * 10^25 * (2.36 * 10^4)²
K. E. = 1.95 * 10³⁴ J
Ohhhhh its called a input machine
Answer:
Being a plane mirror the Image is formed 3 metres beyond the mirror . So total distance is 3+3 = 6metres
