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3 years ago

Convert 500ml to how many liters

Physics

2 answers:

Mashutka [201]3 years ago

7 0

500 ml = 0.5 liters. that's what i'm getting

hope it helps

Lilit [14]3 years ago

5 0

(500 mL) · (1 liter / 1,000 mL)

= (500 / 1,000) liter

= 1/2 liter

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While walking along the shore of a lake Travis felt a cold breeze. What type of heat energy transfer is this an example of?

AfilCa [17]

Out of the 3 types of heat transfer, this scenario would be most likely to be an example of convection.

Convection is where the transferring of heat is resulted through the movements of fluid, but in this case it is air. What happens is that when a part of the whole mass of air is heated, the hotter air rises and the cooler air descends and takes place of the hotter air before it was heated. Then, the cooler air becomes hotter and the hotter air before becomes the cooler air of both, which then results to the repeat of the exchange of places. This creates a motion until the whole mass has achieved mutual temperature, the heat source has stopped or extinguished, or there is a shift of temperature.

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3 years ago

M84, M87, and NGC 4258 all have accretion disks around their central black holes for which the rotational velocities have been m

givi [52]

Answer:

For M84:

M = 590.7 * 10³⁶ kg

For M87:

M = 2307.46 * 10³⁶ kg

Explanation:

1 parsec, pc = 3.08 * 10¹⁶ m

The equation of the orbit speed can be used to calculate the doppler velocity:

$v = \sqrt{\frac{GM}{r} }$

making m the subject of the formula in the equation above to calculate the mass of the black hole:

$M = \frac{v^{2} r}{G}$ .............(1)

For M84:

r = 8 pc = 8 * 3.08 * 10¹⁶

r = 24.64 * 10¹⁶ m

v = 400 km/s = 4 * 10⁵ m/s

G = 6.674 * 10⁻¹¹ m³/kgs²

Substituting these values into equation (1)

$M = \frac{( 4*10^{5}) ^{2} *24.64* 10^{16} }{6.674 * 10^{-11} }$

M = 590.7 * 10³⁶ kg

For M87:

r = 20 pc = 20 * 3.08 * 10¹⁶

r = 61.6* 10¹⁶ m

v = 500 km/s = 5 * 10⁵ m/s

G = 6.674 * 10⁻¹¹ m³/kgs²

Substituting these values into equation (1)

$M = \frac{( 5*10^{5}) ^{2} *61.6* 10^{16} }{6.674 * 10^{-11} }$

M = 2307.46 * 10³⁶ kg

The mass of the black hole in the galaxies is measured using the doppler shift.

The assumption made is that the intrinsic velocity dispersion is needed to match the line widths that are observed.

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3 years ago

You are traveling on an interstate highway at the posted speed limit of 70 mph when you see that the traffic in front of you has

vovikov84 [41]

Answer:8.75 s,

136.89 m

Explanation:

Given

Initial velocity $=70 mph\approx 31.29 m/s$

velocity after 5 s is $30 mph\approx 13.41 m/s$

Therefore acceleration during these 5 s

$a=\frac{v-u}{t}$

$a=\frac{13.41-31.29}{5}=-3.576 m/s^2$

therefore time required to stop

v=u+at

here v=final velocity =0 m/s

initial velocity =31.29 m/s

$0=31.29-3.576\times t$

$t=\frac{31.29}{3.576}=8.75 s$

(b)total distance traveled before stoppage

$v^2-u^2=2as$

$0^2-31.29^2=2\times (-3.576)\cdot s$

s=136.89 m

3 0

3 years ago

The gasoline in a car does 40,000 J of work on a car and generates a constant force of 20 N. How far did the car go?

AnnyKZ [126]

L=F•d=>d=L/F=40,000/20=2,000 m

7 0

3 years ago

A 5.0 kg object moving at 5.0 m/s. KE = mv2 times 1/2

steposvetlana [31]

Answer: KE = 62.5J

Explanation:

Given that

Mass of object = 5kg

kinetic energy KE = ?

velocity of object = 5m/s

Since kinetic energy is the energy possessed by a moving object, and it depends on the mass (m) of the object and the velocity (v) by which it moves. Therefore, the object has kinetic energy.

i.e K.E = 1/2mv^2

KE = 1/2 x 5kg x (5m/s)^2

KE = 0.5 x 5 x 25

KE = 62.5J

Thus, the object has 62.5 joules of kinetic energy.

5 0

3 years ago