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Lady_Fox [76]
3 years ago
7

Convert 500ml to how many liters

Physics
2 answers:
Mashutka [201]3 years ago
7 0

500 ml = 0.5 liters. that's what i'm getting

hope it helps

Lilit [14]3 years ago
5 0

                    (500 mL) · (1 liter / 1,000 mL)

                 =    (500 / 1,000)  liter

                 =      1/2 liter
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. A block of mass 4.0 kg on a spring has displacement as a function of time given by, x (t) = (1.0 cm) cos [(2.0 rad/s) t + 0.25
svlad2 [7]

Answer and Explanation:

1. Evaluate the function x(t) at t=0.5

x(t)=1cos(2t+0.25)\\x(0.5)=cos(2*0.5+0.25)=cos(1+0.25)=cos(1.25)=0.3153223624\approx0.31cm

2. The period of motion T can be calculated as:

T=\frac{2\pi}{\omega}

Where:

\omega=2rad/s

So:

T=\frac{2\pi}{2}=\pi\approx3.14s

3. The angular frequency can be expressed as:

\omega=\sqrt{\frac{k}{m} }

Solving for k:

k=(\omega)^2*m=(2)^2*4=4*4=16\frac{N}{m}

4. Find the derivate of x(t):

\frac{dx}{dt} =v(t)=-2sin(2t+0.25)

Now, the sine function reach its maximum value at π/2 so:

2t+025=\frac{\pi}{2}

Solving for t:

t=\frac{\frac{\pi}{2} -0.25}{2} =0.6603981634s

Evaluating v(t) for 0.6603981634:

v(0.6603981634)=-2sin(2*0.6603981634+0.25)=-2sin(\frac{\pi}{2} )=-2*1=2

So the maximum speed of the block is:

v(0.6603981634)=2cm/s=0.02m/s

In the negative direction of x-axis

5. The force is given by:

F=kx

The cosine function reach its maximum value at 2π so:

2t+0.25=2\pi

Solving for t:

t=\frac{2\pi-0.25}{2} =3.016592654s

Evaluating x(t) for 3.016592654:

x(3.016592654)=cos(2*3.016592654+0.25)=cos(2\pi)=1cm=0.01m

Therefore the the maximum force on the block is:

F=16*0.01=0.16N

6 0
3 years ago
Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is
Anestetic [448]

The electrical force between the two charges can be calculated as +1.8×10⁻² N and its repulsive.

To find the electrical force, distance = 2 meters

charge q1 = 2×10⁻⁶ C

charge q2 = 4×10⁻⁶ C

<h3>Define coulomb's law and solve with formula.</h3>

         The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.

Formula can be written as,

          F = K ( q1q2 / r² )

F - electric force

k - Coulomb constant

q1, q2 - charges

r - distance of separation

Substituting the values in the formula,

         F = 9 × 10⁹ Nm²/C² ( (2×10⁻⁶ C ×  4×10⁻⁶ C) / (2²))

            = 0.0179751

         F = 1.8 × 10 ⁻² N.

As both the charges q1 and q2 are positive, the charges gets repulsive.

SO, the correct answer is Option A.

Learn more about coulomb's law,

brainly.com/question/506926

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8 0
2 years ago
Blown balloon kept outside on a sunny day bursts what will happen to the ballon​
Advocard [28]

When the balloon is kept in the sun, due to Sun's heat, the kinetic energy of gaseous particles inside the balloons also gets increased and the balloon expands. This will increase the pressure on the walls of the balloon. It continues to expand and comes to a stage when the baloon bursts.

5 0
3 years ago
A rectangular pool has a volume of 375 m3. the pool is 10 m long and 5 m wide. how deep is the pool? 7.5 m 3,750 m 75 m
likoan [24]
V=L•W•H. Sub in what you know: 375=10•5•H. Simplify: 375=50H. Divide by 50: 375/50=H. H=7.5 :)
6 0
3 years ago
Read 2 more answers
The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the
seraphim [82]

Answer:

x=\dfrac{D}{1+\sqrt{\dfrac{m}{M}}}

Explanation:

Mass of moon = m

Mass of planet =M

We know that gravitational force given as

F=G\dfrac{m_1m_2}{d^2}

F'=G\dfrac{m'M}{x^2}

F=G\dfrac{m'm}{(D-x)^2}

Given that force is zero so

F=F'

G\dfrac{m'm}{(D-x)^2}=G\dfrac{m'M}{x^2}

\dfrac{m}{(D-x)^2}=\dfrac{M}{x^2}

\dfrac{x}{D-x}=\sqrt{\dfrac{M}{m}}

\dfrac{D-x}{x}=\sqrt{\dfrac{m}{M}}

x=\dfrac{D}{1+\sqrt{\dfrac{m}{M}}}

6 0
3 years ago
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