Answer:
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Answer: 4. Twice as much
Explanation:
Potential energy of an object is given by the equation
PE= mgh (where m is the mass, g is the acceleration due to gravity and h is its vertical distance above ground level)
If it were lifted twice its initial height,
PE = mgH (where H is the new height, which is twice the initial vertical distance)
PE = mg(2h)
PE = 2mgh
We can see that the potential energy doubles as the vertical distance is doubled.
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Answer:
Emf induced in the loop is 0.02V
Explanation:
To get the emf of induced loop, we have to use faraday's law
ε = - dΦ/dt
To get the flux, we use;
Φ = BA cos(θ)
B = The uniform magnetic field
A = Area of rectangular loop
θ = angle between magnetic field and normal to the plane of loop
substitute the flux equation (Φ) into the faraday's equation
we have ε = - d(BA cos(θ)) / dt
ε = BA sinθ dθ/dt
from the question;B = 0.18T, A=0.15m2, θ = π/2 ,dθ/dt = 0.75rad/s
Our equation will now look like this;
ε = (0.18T) (0.15m2) (sin(π/2)) (0.75rad/s)
ε = 0.02V