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liraira [26]
2 years ago
9

Answer the question below please I give brainliest

Physics
2 answers:
Basile [38]2 years ago
7 0

Answer: The first one

Explanation: I think it's the first one because it says what is the "least" gravitational potential energy story between the prairie dog and Earth that said resting in its borrow is using less energy

blondinia [14]2 years ago
6 0
When the prairie dog was in the burrow because that doesn’t use much energy
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Please help me i have this due tommorrow!!!
Ronch [10]
I found this!! maybe this will help :)

8 0
2 years ago
The electric current in a wire is 1.5A. How many electrons flow past a given point in a time of 2s?
kipiarov [429]

Answer:

The amount of electrons that flow in the given time is 3.0 C.

Explanation:

An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.

i.e           I = \frac{Q}{t} ...................(1)

It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.

In the given question, I = 1.5A, t = 2s, find Q.

From equation 1,

            Q = I × t

                = 1.5 × 2

               = 3.0 Coulombs

The amount of electrons that flow in the given time is 3.0 C.

5 0
2 years ago
What is the mechanical advantage of a lever that has an input arm of 6 meters and an output arm of 2 meters
Setler79 [48]

Answer:A

Explanation:I TOOK THE Test

5 0
3 years ago
Which of the following is a noncontact force? A. electrical forces B. gravitational forces C. magnetic forces D. all of these
goblinko [34]
D. all of these

hope this helps.
6 0
3 years ago
Read 2 more answers
A child of mass 27 kg swings at the end of an elastic cord. At the bottom of the swing, the child's velocity is horizontal, and
snow_tiger [21]

Answer:

The magnitude of the rate of change of the child's momentum is 794.11 N.

Explanation:

Given that,

Mass of child = 27 kg

Speed of child in horizontal = 10 m/s

Length = 3.40 m

There is a rate of change of the perpendicular component of momentum.

Centripetal force acts always towards the center.

We need to calculate the magnitude of the rate of change of the child's momentum

Using formula of momentum

\dfrac{dp}{dt}=F

\dfrac{dP}{dt}=\dfrac{mv^2}{r}

Put the value into the formula

\dfrac{dP}{dt}=\dfrac{27\times10^2}{3.40}

\dfrac{dP}{dt}=794.11\ N

Hence, The magnitude of the rate of change of the child's momentum is 794.11 N.

7 0
3 years ago
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