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SashulF [63]
3 years ago
15

How should the flight controls be held while taxiing a tricycle-gear equipped airplane with a left quartering tailwind?

Physics
1 answer:
AlexFokin [52]3 years ago
5 0
<span>The flight controls must be held with left aileron up and elevator neutral while taxiing a tricycle-gear equipped airplane with a left quartering tailwind. In aircraft, ailerons are placed on the trailing edge of each wing near the wingtips and can be moved up and down. So when the left aileron is up, the movement of the airplane moves to the left  and turns the wheel in a counterclockwise direction while at the same time, the right aileron is down.
</span>
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A student is trying to demonstrate static electricity, so they rub two identical balloons with a neutral rabbit fur to give them
Maksim231197 [3]

You can download answer here

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3 0
3 years ago
Can anyone solve this?
love history [14]

Answer:

F = 39.2 N

Explanation:

Since, the object is in uniform motion. Therefore, the frictional force on object will be:

Frictional Force = μk N = μk mg

where,

μk = coefficient of kinetic friction = 0.2

m = mass of crate = 10 kg

g = 9.8 m/s²

Therefore,

Frictional Force = (0.2)(10 kg)(9.8 m/s²)

Frictional Force = 19.6 N

The horizontal component of force must be equal to this frictional force to continue the uniform motion:

F Sin 30° = 19.6 N

F = 19.6 N/Sin 30°

<u>F = 39.2 N</u>

3 0
3 years ago
After watching the video below and based on your personal experiences, is there a difference
jek_recluse [69]

Based on my personal experiences, I believe that there is a difference between areas in precision of control because there are different part of the brain that controls the functions of the body.

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From the standpoint of  brain lateralization, differences do exist such as based on experience such as handedness or specific skills such as playing a guitar.

Note that Left-handers are said to have reduced or little lateralized brains, which tells us that the two halves of the brain are little different than as seen in the right-handers.

Therefore, I can say that based on my personal experiences, I believe that there is a difference between areas in precision of control because there are different part of the brain that controls the functions of the body.

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3 0
2 years ago
A pipe is horizontal and carries oil that has a viscosity of 0.14 Pa s. The volume flow rate of the oil is 5.3 × 10-5 m3/s. The
Liula [17]

Answer:

Explanation:

Given

\mu =0.14 Pa.s

Volume Flow rate Q=5.3\times 10^{-5} m^3/s

Length L=37 m

radius r=0.58 cm

D=1.16 cm

According to Hagen-Poiseuille Equation

difference in Pressure is given

\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}-P_{out}=\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}=P_{out}+\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}=1.01325\times 10^5+\frac{128\times 0.14\times 37\times 5.3\times 10^{-5}}{\pi\cdot 1.16^4\times 10^{-8}}

P_{in}=1.01325\times 10^5+6.17\times 10^5

P_{in}=7.19\times 10^5

3 0
3 years ago
The small piston of a hydraulic lift has a cross-sectional of 3 00 cm2 and its large piston has a cross-sectional area of 200 cm
Nesterboy [21]

Q: The small piston of a hydraulic lift has a cross-sectional of 3.00 cm2 and its large piston has a cross-sectional area of 200 cm2. What downward force of magnitude must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN?

Answer:

225 N

Explanation:

From Pascal's principle,

F/A = f/a ...................... Equation 1

Where F = Force exerted on the larger piston, f = force applied to the smaller piston, A = cross sectional area of the larger piston, a = cross sectional area of the smaller piston.

Making f the subject of the equation,

f = F(a)/A ..................... Equation 2

Given: F = 15.0 kN = 15000 N, A = 200 cm², a = 3.00 cm².

Substituting into equation 2

f = 15000(3/200)

f = 225 N.

Hence the downward force that must be applied to small piston = 225 N

8 0
3 years ago
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