Answer:
Step-by-step explanation:
To find an equation of the sphere with center (4, −12, 8) and radius 10
intersection with xy-plane
Put z=0
(A circle with centre at (4,-12) and radius 6)
intersection with xz-plane
Put y =0
Sum of squares cannot be positive, so DNE
intersection with yz-plane
Put x=0
A circle in YZ plane with centre at y =-12 and z =8 and radius square root of 84
Answer:
840
Step-by-step explanation:
i dont really know
4,2,0,-2,-4,-6,-8,-10 because you subtract 2 each time
Answer:
9² = 40² + 41² - 2(40)(41) cos(C)
81 = 1600 + 1681 - 3280 cos(C)
81 = 3281 - 3280 cos(C)
-3200 = -3280 cos(C)
cos(C) = 3200 / 3280
cos(C) = 40 / 41
Step-by-step explanation: