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3 years ago

A __________ is an added note showing additional or more specific information.

Engineering

1 answer:

xxMikexx [17]3 years ago

8 0

Answer:

awnsers should be added to know to show additional

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The normal stress at gage H calculated in Part 1 includes four components: an axial component due to load P, σaxial, P, a bendin

Degger [83]

Answer:

hello your question has some missing information attached to the answer is the missing component

Answer : αaxial,p = -6.034 ksi ( compressive )

αbend,p = 19.648 ksi ( tensile )

Explanation:

αaxial, p = $\frac{-p}{A}$ equation 1

αbend, p = $\frac{(P*A)*\frac{d}{2} }{I_{z} }$ equation 2

P = load = 35 kips

A = area of column = 5.8 $in^{2}$

d = column cross section depth = 9.5 in

$I_{Z}$ = 55.0 $in^{4}$

Hence equation 1 becomes

αaxial,p = -35 / 5.8 = - 6.034 ksi ( compressive )

equation 2 becomes

αbend, p = $\frac{(35*6.5)(\frac{9.2}{2}) }{55}$ = + 19.648 ksi ( tensile )

7 0

3 years ago

3Px=y−y2p2<br><br>first order higher dgree

dlinn [17]

Answer:

the order higher is 3p79g5t88=yv5379

7 0

2 years ago

How does warming up the tires on a car increase grip with the pavement?

ICE Princess25 [194]

Answer:

because burning rubber increases the grip power

8 0

2 years ago

Using the Rayleigh criterion, calculate the minimum feature size that can be resolved in a system with a 0.18 NA lens when g-lin

Vladimir79 [104]

Answer:

# for a g line, R = 1.211 μm

# for an I-line, R = 1.013 μm

# for a g line, R = 0.726 μm

# for an I-line, R = 0.243 μm

# for a g line, R = 0.605 μm

# for an I-line, R = 0.608 μm

Explanation:

We know that;

Rayleigh Resolution R = 0.5 × λ/NA

for a g line, λ = 436 nm

for an I-line λ = 365 nm

Now when NA = 0.18

# for a g line, λ = 436 nm

R = 0.5 × 436/0.18 = 1.211 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.18 = 1.013 μm

when NA = 0.30

# for a g line, λ = 436 nm

R = 0.5 × 436/0.30 = 0.726 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.30 = 0.243 μm

when NA = 0.36

# for a g line, λ = 436 nm

R = 0.5 × 436/0.36 = 0.605 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.30 = 0.608 μm

6 0

3 years ago

Find a negative feedback controller with at least two tunable gains that (1) results in zero steady state error when the input i

IceJOKER [234]

Answer:

Gc(s) = $\frac{0.1s + 0.28727}{s}$

Explanation:

comparing the standard approximation with the plot attached we can tune the PI gains so that the desired response is obtained. this is because the time requirement of the setting is met while the %OS requirement is not achieved instead a 12% OS is seen from the plot.

attached is the detailed solution and the plot in Matlab

8 0

3 years ago