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vovikov84 [41]
3 years ago
5

If the resulting trajectory of the charged particle is a circle,what is , the angular frequency of the circular motion?Express i

n terms of ,w,m and B0 .
Physics
1 answer:
Maru [420]3 years ago
8 0

Answer:

ω = B₀q/m

Explanation:

The centripetal force on the charge equal the magnetic force on the charge. (Since the trajectory is a circle). So, mrω² = B₀qv.

v = rω The speed of the charge and r = radius of path

mrω² = B₀qrω

ω = B₀q/m

The angular frequency ω = B₀q/m

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Explanation:

<u>FOR NUMBER OF MOLECULES</u>:

No.\ of\ Molecules = (No.\ of\ Moles)(Avigadro's\ Number)\\No.\ of\ Molecules = (3)(6.02\ x\ 10^{23}\ molecules})\\

<u>No. of Molecules = 18.06 x 10²³ molecules</u>

<u></u>

<u>FOR NUMBER OF P ATOMS</u>:

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<u>No. of Atoms of P = 3 atoms</u>

<u></u>

<u>FOR NUMBER OF Na ATOMS</u>:

No.\ of\ Atoms\ of\ Na = (No.\ of\ Moles)(N.\ of atoms of Na)\\No.\ of\ Atoms\ of\ Na = (3)(3\ atom})

<u>No. of Atoms of Na = 9 atoms</u>

<u></u>

<u>FOR TOTAL NUMBER OF ATOMS</u>:

Total\ No.\ of\ Atoms = (No.\ of\ Moles)(N.\ of\ atoms\ of\ Na + No.\ of\ atoms\ of\ P + No.\ of\ atoms\ of\ O)\\ Total\ No.\ of\ Atoms\ = (3)(3\ atoms + 1\ atom + 4\ atoms}) = (3)(8\ atoms)

<u>Total No. of Atoms = 24 atoms</u>

<u></u>

<u></u>

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