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dem82 [27]
4 years ago
5

Kellie jogs 6.0 km in 54 minutes, then 1.0 km in 16 minutes. What is her average speed in km/min please show your work

Physics
1 answer:
satela [25.4K]4 years ago
3 0

Answer:

Vprom = 0.00347[km/min]

Explanation:

We can calculate each of the average speeds and then perform the overall average between the two speeds.

V1 = 6/54

V1 = 0.111[km/min]

V2 = 1/16

V2 = 0.0625[km/min]

V_{prom} = \frac{V_{1} + V_{2}}{2}  \\V_{prom} = \frac{0.1111 + 0.0625}{2}\\V_{prom} = 0.00347 [km/min]

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In both cases plates are moving away from one another. Therefore they are creating new land masses.

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When the distance between two masses is doubled, the gravitational attraction between
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The new gravitational attraction will be 1/4 as much

Explanation:

The magnitude of the gravitational force between two objects is given by

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In this problem, the original force between the two objects is F, when they are separated by a distance r.

Later, the distance between the two objects is doubled, so the new distance is

r'=2r

Therefore, the new force will be

F'=G\frac{m_1 m_2}{(2r)^2}=\frac{1}{4}(\frac{Gm_1 m_2}{r^2})=\frac{F}{4}

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A spring with spring constant of 34 N/m is stretched 0.12 m from its equilibrium position. How much work must be done to stretch
Nesterboy [21]

Answer:0.253Joules

Explanation:

First, we will calculate the force required to stretch the string. According to Hooke's law, the force applied to an elastic material or string is directly proportional to its extension.

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