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dem82 [27]
3 years ago
5

Kellie jogs 6.0 km in 54 minutes, then 1.0 km in 16 minutes. What is her average speed in km/min please show your work

Physics
1 answer:
satela [25.4K]3 years ago
3 0

Answer:

Vprom = 0.00347[km/min]

Explanation:

We can calculate each of the average speeds and then perform the overall average between the two speeds.

V1 = 6/54

V1 = 0.111[km/min]

V2 = 1/16

V2 = 0.0625[km/min]

V_{prom} = \frac{V_{1} + V_{2}}{2}  \\V_{prom} = \frac{0.1111 + 0.0625}{2}\\V_{prom} = 0.00347 [km/min]

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A steel piano wire, of length 1.150 m and mass 4.80 g is stretched under a tension of 580.0 N.
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A steel piano wire, of length 1.150 m and mass of 4.80 g is stretched under a tension of 580.0 N.the speed of transverse waves on the wire would be  372.77 m/s

<h3>What is a sound wave?</h3>

It is a particular variety of mechanical waves made up of the disruption brought on by the movements of the energy. In an elastic medium like the air, a sound wave travels through compression and rarefaction.

For calculating the wave velocity of the sound waves generated from the piano can be calculated by the formula

V= √F/μ

where v is the wave velocity of the wave travel on the string

F is the tension in the string of piano

μ is the mass per unit length of the string

As given in question a steel piano wire, of length 1.150 m and mass of 4.80 g is stretched under a tension of 580.0 N.

The μ is the mass per unit length of the string would be

μ = 4.80/(1.150×1000)

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By substituting the respective values of the tension on the string and the density(mass per unit length) in the above formula of the wave velocity

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Thus,  the speed of transverse waves on the wire comes out to be  372.77 m/s

Learn more about sound waves from here

brainly.com/question/11797560

#SPJ1

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