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4 years ago

O2 is a molecule.

1 answer:

5 0

1. true is the answer
2. The correct option is this: FIGURE II AND FIGURE IV ARE BOTH COMPOUNDS.Figure two and figure four have components that are of different colors, this means that different atoms had combined together to form a compound.3. dont know yet
4. The figure is a molecule and an element is the correct answer
5. Elements
6. Co2
7. Both are made of two or more atoms.
8. the answer is atom

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A person rides a Ferris wheel that turns with constant angular velocity. Her weight is 549.0 N. At the top of the ride her appar

pashok25 [27]

Answer:

Explanation:

Given that the angular velocity is constant.

The actual weight is W = 549N

The ride apparent weight is

W' = 1.5N

Apparent weight at the top of the ride?

Using newton second law of motion

ΣF = m•ar

ar is the radial acceleration

N — W = —m•ar

N = W —m•ar

N = mg —m•ar

N = m(g—ar)

The apparent weight is equal to the normal

W'(top) = N = m(g—ar)

W'(top) = m(g—ar)

W'(top) = mg —m•ar

We know that the actual weight is

W=mg

Also, the apparent weight is

W' = m•ar

Then

W'(top) = Actual weight - apparent

W'(top) = 549—1.5

W'(top) = 547.5 N

8 0

4 years ago

A bugle can be thought of as an open pipe. If a bugle were straightened out, it would be 2.65 mlong.a.) If the speed of sound is

Nezavi [6.7K]

Answer:

(a). The lowest frequency is 64.7 Hz.

(b). The next two resonant frequencies for the bugle are 129.4 Hz and 194.2 hz.

Explanation:

Given that,

Length = 2.65 m

Speed of sound = 343 m

We need to calculate the wavelength

Using formula of wavelength

$\lambda=2l$

Put the value into the formula

$\lambda=2\times2.65$

$\lambda=5.3\ m$

(a). We need to calculate the lowest frequency

Using formula of frequency

$f_{1}=\dfrac{v}{\lambda_{1}}$

Put the value into the formula

$f_{1}=\dfrac{343}{5.3}$

$f_{1}=64.7\ Hz$

(b). We need to calculate the next two resonant frequencies for the bugle

Using formula of resonant frequency

$f_{2}=\dfrac{v}{\lambda_{2}}$

$f_{2}=\dfrac{v}{l}$

Put the value into the formula

$f_{2}=\dfrac{343}{2.65}$

$f_{2}=129.4\ Hz$

For third frequency,

$f_{3}=\dfrac{v}{\lambda_{3}}$

$f_{3}=\dfrac{3v}{2l}$

Put the value into the formula

$f_{3}=\dfrac{3\times343}{2\times2.65}$

$f_{3}=194.2\ Hz$

Hence, (a). The lowest frequency is 64.7 Hz.

(b). The next two resonant frequencies for the bugle are 129.4 Hz and 194.2 hz.

3 0

3 years ago

What are the three reasons why nebula contribute more to Stellar formation than any other region in the universe?

monitta

I think it is a, b, and e. Hope it helps! :)

7 0

4 years ago

Read 2 more answers

A concrete slab of mass 400 kg accelerates down a concrete slope inclined at 35°. The kinetic between the slab and slope is 0.60

belka [17]

I got you

Explanation:

normal force = 400 g cos 35

friction force up slope = .6 (400 g) cos 35

weight component down slope = 400 g sin 35

400 a = 400 g sin 35 - .6 (400 g cos 35)

a = g (sin 35 - .6 cos 35) = .082 g

I hope this helps you

8 0

2 years ago

What does the atomic number tell us about an atom of a certain element?

Setler79 [48]

It tells us the number of protons that are present in the nucleus, the positively charged region of that atom.

4 0

3 years ago