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Olenka [21]
3 years ago
12

Calculate the accleration of a 25-Kg object that moved with force of 300 N

Physics
1 answer:
inysia [295]3 years ago
4 0
F=ma
a=F/m=300/25=12 m/s^2
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A car travels straight for 20 miles on a road that is 30 degrees north of east what is the east component of the cars displaceme
EleoNora [17]
17.3 boiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
3 0
3 years ago
Suppose you first walk 12.0 m in a direction 200 west of north and then 20.0 m in a direction 40.00 south of west. How far are y
Tpy6a [65]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

the compass direction of the resultant displacement is  \theta  =4.7^o south of west

Explanation:

Generally using cosine we can obtain the resultant R as follows

     R^2  =  A^2  + B^2 -2ABcos(70)

=>   R  =  \sqrt{12^2  + 20^2  - 2(12 ) *  (20) cos  70}

=>    R  =  19.48 \  m

We can obtain the direction of the resultant by first  using sine rule to obtain angle C as follows

       \frac{A}{sin  C}  =  \frac{R}{sin70 }

=>    C=  sin ^{-1} [\frac{A *  (sin 70)}{R} ]

=>    C =  sin ^{-1} [\frac{20 *  (sin 70)}{19.48} ]

=>  C =  74.7 ^o

Then the direction is obtained as

       \theta  =  C  -  70

=>    \theta  = 74.7   -  70

=>     \theta  =4.7^o

Hence the compass direction of the resultant displacement is  \theta  =4.7^o south of west

7 0
3 years ago
The impulse given to a ball with massb of 2kg is 16 Ns. if the ball starts grin the rest, what is its final velocity?
Ainat [17]
B because it will not be any thing else

6 0
3 years ago
What are the forces that make an object move
Vaselesa [24]
There are many forces that make an object move.

· An Unbalanced force acting on an object

· Energy applied to an object.


3 0
3 years ago
Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) With what initial velo
alukav5142 [94]

Answer:

v_i=189.315ft/s

Explanation:

We are going to use the accelerated motion formula v_f^2=v_i^2+2ad on the vertical component taking the upwards direction as positive.

Since <em>at maximum height the speed will be v_f=0m/s</em>, the formula can be written as v_i=\sqrt{-2ad}, which for our values is:

v_i=\sqrt{-2(-32ft/s^2)(560ft)}=189.314553059ft/s=189.315ft/s

Written to three decimal places.

3 0
4 years ago
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