“When we move down a group then there is increase in the size of elements because there occurs increase in atomic mass of the elements.
It means that there occurs increase in number of electrons due to which there will be increase in number of new shells. As a result, size of atom or element increases due to which there is increase in atomic radius of the element.
Therefore, we can conclude that increase in number of electrons makes the atomic radius change down a column of the periodic table.”
Answer:
Q = 0.144
Explanation:
- C(s) + H2O(g) ↔ CO(g) + H2(g)
reaction quotient:
- Q = [H2(g)][CO(g)] / [H2O(g)][C(s)]
∴ [C(s)] = 10.0 mol/2.50 L = 4 M
∴ [H2O(g)] = 16.0 mol/2.50 L = 6.4 M
∴ [CO(g)] = 3.30 mol/2.50 L = 1.32 M
∴ [H2(g)] = 7.00 mol/2.50 L = 2.8 M
⇒ Q = (2.8 M)(1.32 M) / (6.4 M)(4 M)
⇒ Q = 0.144
Answer:
Option c. is correct
Explanation:
A chemical bond enables the formation of chemical compounds depending on the nature of the participating atoms like atoms, ions or molecules.
These are formed as a result of the force of attraction between oppositely charged ions.
It is formed by the overlapping of the atomic orbitals of the two atoms.
When the length of a chemical bond is short an electron is held tighter and the bond is stronger
For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.
From the problem, you know that 1) = 2.000 g.
Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).
1) = 5.022 g - 3.715 g = 1.307 g
Now you can complete our original task.
Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.
It would be solid
hope this helps
