Ammonia is the most basic and has the highest OH- concentration since it has the highest pH.
Answer:
2C(s, graphite)+ 3H₂(g) + ½O₂(g) ⟶ C₂H₅OH(ℓ)
Explanation:
The thermodynamic standard state of elements and compounds is defined as their most stable state at 25 °C and 1 bar
The elements in ethanol, C₂H₅OH, are C, H, and O.
Their most stable states at standard conditions are C₂H₅OH(ℓ), C(s, graphite), H₂(g), and O₂(g)
The equation for the formation of ethanol from its elements is then
2C(s, graphite) + 3H₂(g) + ½O₂(g) ⟶ C₂H₅OH(ℓ)
Answer:-
KOH determines how much Mg(OH)2 is made.
2 mol of Mg(OH)2 formed
Explanation:-
The balanced equation is
MgCl2 + 2KOH --> Mg(OH)2+ 2KCI,
From seeing the coefficients we notice
2 mol of KOH reacts with 1 mol of MgCl2
4 mol of KOH reacts with 1 x 4 / 2 = 2 mol of MgCl2
3 moles of MgCl2 was added but only 2 mol react.
So we see there is excess MgCl2 .
Hence KOH is the limiting reactant.
So KOH determines how much Mg(OH)2 is made.
We see from the balanced chemical equation,
2 mol of KOH gives 1 mol of Mg(OH)2.
4 mol of KOH will give 1 x 4 /2 = 2 mol of Mg(OH)2.
It is bases on "Atomic number"
In short, Your Answer would be Option B
Hope this helps!
Answer:
The answer to your question is:
Vol of NO2 = 11.19 L
Vol of O2 = 2.8 L
Explanation:
Data
N2O5 = 56 g
STP T = 0°C = 273°K
P = 1 atm
MW N2O5 = 216 g
Gases law = PV = nRT
Process
216 g of N2O5 ---------------- 1 mol
54 g ----------------- x
x = (54 x 1) / 216
x = 0.25 mol of N2O5
2 mol of N2O5 ----------------- 4 mol of NO2
0.25 mol ------------------ x
x = (0.25 x 4) / 2 = 0.5 mol of NO2
V = nRT/P
V = (0.5)(0.082)(273) / 1 = 11.19 L
2 mol of N2O5 ----------------- 1 O2
0.25 N2O5 ---------------------- x
x = (0.25 x 1) / 2 = 0.125 mol
Vol = (0.125)((0.082)(273) / 1 = 2.8 L
