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TEA [102]
3 years ago
9

Describe the major types of bodies of water

Chemistry
1 answer:
Alina [70]3 years ago
4 0
<h2>Answer and Explanation </h2>

The body of water means the occurrence of water on earth’s surface. Examples are oceans,  lakes,  seas, ponds, and pools. The major bodies of water are:

  • Pacific ocean is the biggest and deepest of Earth's oceanic divisions. It stretches from the Arctic Ocean in the direction to the Southern Ocean.
  • Atlantic ocean is another giant of the world's oceans.  It includes nearly 20 percent of the Earth's exterior and nearly 29 percent of its water covering space.
  • The Indian Ocean is the third largest Ocean in the world. It is surrounded by Asia, Africa, and Australia.
  • Arctic ocean is the smallest and shallowest of the world's five main oceans.
  • Mediterranean sea is a sea is attached to the Atlantic Ocean.
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When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --&gt; 2 AlCl3 (s) c) How many moles of the e
sineoko [7]

Answer:

The answer to your question is 1.49 mol of Cl₂  

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

                2 Al(s)  +  3Cl₂(g)  ⇒   2AlCl₃

Process

a) Calculate the molar mass of the reactants  

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion  Al/Cl₂ = 53.96/212.7 = 0.254

   Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

                    53.96 g of Al ------------------ 212.7 g of Cl₂

                     40.5 g of Al -------------------  x

                      x = (40.5 x 212.7) / 53.96

                      x = 8614.35 / 53.96

                      x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

                  = 53.057 g

d) Calculate the moles of Cl

                       35.45 g of Cl ----------------- 1 mol

                       53.057 g of Cl ---------------  x

                        x = (53.057 x 1)/35.45

                       x = 1.49 mol of Cl₂                    

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Answer:

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