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TEA [102]
3 years ago
9

Describe the major types of bodies of water

Chemistry
1 answer:
Alina [70]3 years ago
4 0
<h2>Answer and Explanation </h2>

The body of water means the occurrence of water on earth’s surface. Examples are oceans,  lakes,  seas, ponds, and pools. The major bodies of water are:

  • Pacific ocean is the biggest and deepest of Earth's oceanic divisions. It stretches from the Arctic Ocean in the direction to the Southern Ocean.
  • Atlantic ocean is another giant of the world's oceans.  It includes nearly 20 percent of the Earth's exterior and nearly 29 percent of its water covering space.
  • The Indian Ocean is the third largest Ocean in the world. It is surrounded by Asia, Africa, and Australia.
  • Arctic ocean is the smallest and shallowest of the world's five main oceans.
  • Mediterranean sea is a sea is attached to the Atlantic Ocean.
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So, a gas, and an
valina [46]

Answer:

d) cut the large sized Cu solid into smaller sized pieces

Explanation:

The aim of the question is to select the right condition for that would increases the rate of the reaction.

a) use a large sized piece of the solid Cu

This option is wrong. Reducing the surface area decreases the reaction rate.

b) lower the initial temperature below 25 °C for the liquid reactant, HNO3

Hugher temperatures leads to faster reactions hence this option is wrong.

c) use a 0.5 M HNO3 instead of 2.0 M HNO3

Higher concentration leads to increased rate of reaction. Hence this option is wrong.

d) cut the large sized Cu solid into smaller sized pieces

This leads to an increased surface area of the reactants, which leads to an increased rate of the reaction. This is the correct option.

5 0
3 years ago
Can I get help with this, please!!
kondor19780726 [428]

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

Explanation:

Pressure in the submarine = 108.9 kPa

Volume, V = 2.4 * 10^5 L

Pressure, P = 116k Pa

Temperature, T = 312 K

Ideal gas law: PV = nRT  or  n = PV / RT

So, moles of gas, n =116 KPa * 2.4 * 10 ^5L / 8.314 LK Pa K^-1 *312 K

= 1.073 *10^4 mol

when temperature is changed to 293K,

PV = nRT  or P = nRT / V

=1.073 *10^4 mol *8.314 LK Pa mol^-1 K^-1 *293 K / 2.4*10^5L

=108.9 K Pa

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

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