Question

The balanced equation below shows the products that are formed when pentane (C₅H₁₂) is combusted. /?f=C_5H_%7B12%7D%20%2B%208O_2%20%5Crightarrow%2010CO_2%20%2B%206H_2O" id="TexFormula1" title="C_5H_{12} + 8O_2 \rightarrow 10CO_2 + 6H_2O" alt="C_5H_{12} + 8O_2 \rightarrow 10CO_2 + 6H_2O" align="absmiddle" class="latex-formula">What is the mole ratio of oxygen to pentane? a. 1:6 b. 6:8 c. 8:1 d. 10:8

Answer 1

Answer:

Option c → 8:1

Explanation:

This is the reaction:

C₅H₁₂ + 8O₂ → 10CO₂ + 6H₂O

1 mol of pentane needs 8 moles of oxygen to be combusted and this combustion produces 10 mol of carbon dioxide and 6 moles of water.

To determine the ratio, look the stoichiometry.

For every 8 moles of oxygen, I need 1 mole of pentane gas.