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iVinArrow [24]
3 years ago
7

Why is my family dissapointed in me?​

Chemistry
2 answers:
ohaa [14]3 years ago
7 0
Probably because you’ve done something like get bad grades, disrespect them, get into trouble, or something like that
Tems11 [23]3 years ago
6 0

Answer:

literally same im failing almost every class and i just know my dad hates me because of it

Explanation:

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Convert 7.72 years into days.
Lelu [443]

Answer:2817.8

Explanation:multiply the value by 365

4 0
3 years ago
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At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?
ahrayia [7]

The standard ambient temperature and pressure are

Temperature =298 K

Pressure = 1atm

The density of gas is 1.5328 g/L

density = mass of gas per unit volume

the ideal gas equation is

PV = nRT

P = pressure = 1 atm

V = volume

n = moles

R= gas constant = 0.0821 Latm/mol K

T = 298 K

moles = mass / molar mass

so we can write

n/V = density / molar mass

Putting values

Pressure=\frac{nRT}{V}=\frac{massXRT}{VXmolarmass}

Pressure=\frac{densityXRT}{molarmass}

molarmass=\frac{densityXRT}{Pressure}=\frac{1.5328X0.0821X298}{1}=37.50

Thus molar mass of gas is 37.50g/mol

6 0
3 years ago
Generators make electricity by _________________ magnets.
scoundrel [369]
As the shaft inside the generator<span> turns, an </span>electric<span> current is produced in the wire. The </span>electric generator<span> is converting mechanical, moving energy into </span>electrical<span>energy. 
-google search</span>
5 0
3 years ago
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When 1.82 moles of HCL reacts with excess MnO2, how many moles of Cl2 form
s2008m [1.1K]

The balanced reaction is:<span>

MnO2(s) + 4HCl(aq) → Cl2(g) + MnCl2(aq) + 2H2O(l)

We are given the amount of hydrochloric acid to be used for the reaction. This will be the starting point for the calculations.

1.82 mol HCl ( 1 mol Cl2 / 4 mol HCl) = 0.46 mol Cl2

<span>Therefore, 0.46 mol of chlorine gas is produced for the reaction of hydrochloric acid and manganese oxide.</span></span>

5 0
3 years ago
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A student heats a sample of hydrate once, and the mass of the sample and the evaporating dish is 16.428 g. After a second heatin
jolli1 [7]

Answer:

12.371 g

Explanation:

Given :

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{evaporating\ dish}+m_{First\ heated\ sample}=16.428\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

Mass of salt hydrate:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{Hydrate\ sample}=25.637-m_{evaporating\ dish}\ g=25.637-1.135\ g=24.502\ g

Mass of salt anhydrous:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

m_{Second\ heated\ sample}=m_{salt\ anhydrous}=13.266-m_{evaporating\ dish}\ g=13.266-1.135\ g=12.131\ g

Mass of water:

m_{water}=m_{Hydrate\ sample}-m_{salt\ anhydrous}=24.502-12.131\ g=12.371\ g

m_{water}=12.371\ g

4 0
3 years ago
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