First you must convert Km/hr to m/s. 90 km/hr equals 25m/s (this can be done through a conversion table by plugging in the conversion values). Then you need to see what was given:
vi (initial velocity)= 0m/s
vf (final velocity= 25m/s (90km/hr)
t (time)= 10s
Next you should find an equation that requires only the values you know and gives you the value you're looking for. Sometimes that requires two equations to be used, but in this case you only need one. The best equation for this would be a=(vf-vi)/t. Finally, plug in your values (a=(25-0)/10) to get your answer which would be 2.5m/s^2. Hope this helped!
We know that;
power=W/t
15000Watts=1800000J/t
t=1800000J/15000Watts
t=120s
Answer:
air or vacuum is the least refractive index medium of most rare medium
all other medium has more value of refractive index and hence the speed will be less than the speed of the air
Explanation:
As we know that speed of light in any medium and speed of light in air is related to each other by the equation

here we know that

[tex]\mu [tex] = refractive index of the medium
so we know that air or vacuum is the least refractive index medium of most rare medium
all other medium has more value of refractive index and hence the speed will be less than the speed of the air
Answer: part 1 is mass and part 2 is density
Explanation: I just did it and got it right
Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4 
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) = 
⇒ P = 
⇒ P = 16 
This is the pressure inside the cylinder.
Let force applied on the brake pad = 
Area of the brake pad (
)= 1.7 
Thus the pressure on the brake pad (
) = 
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P = 
⇒ 16 = 
⇒
= 16 × 
Put the value of
we get
⇒
= 16 × 1.7
⇒
= 27.2 lb
This the total force applied during braking.
The force applied on one wheel =
=
= 6.8 lb
⇒ The force applied on one wheel during braking.