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3 years ago

The principles of magnetism apply everywhere on earth. What does this tell us about God and His character?

Physics

1 answer:

Bas_tet [7]3 years ago

3 0

Answer:

God is omnipresent.

Explanation:

This means God is everywhere and He works where ever we are in the world

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Eric, Sheena, and Yael are playing a game. Eric has half as many points as Sheena. Sheena has two fewer points than Yael. Togeth

nexus9112 [7]

Lets say that:

Eric is E

Sheena is S

Yael is Y

We know that S+2=Y, E= 1/S and that E+S+Y=52. So, we can insert S+2=Y and E= 1/S into our other equation, which would bring us to (1/2S)+(S+2)+S=52. This is equal to 1/2S+S+2+S=52. We then use algebra to get the answer:

Given:

S+2=Y

E=1/S

E+Y+S=52

Equation:

1/2S+S+2+S=52

1/2S+S+S=52

2.5S=50

S=50/2.5

S=20

And since Yael has 2 more points then Yael then we do 20+2 and get 22.

Hope this helps! <3

6 0

3 years ago

In the picture below identify the type of wave in the top picture. *

Lerok [7]

Answer; transverse wave
Explanation;

In transverse waves the particles vibrate perpendicular to the wave's motion.

4 0

3 years ago

Can somebody help please !!!!

Nataly [62]

Vector A is of magnitude 12 m and it makes an angle of 37 degree with Y axis

So here we can say that

$\frac{A_x}{A} = sin37$

$A_x = A sin37$

$A_x = 12 sin37$

$A_x = 7.22 m$

Similarly we have

$\frac{A_y}{A} = cos37$

$A_y = A cos37$

$A_y = 12 cos37$

$A_y = 9.58 m$

So here we have

$A_y = 9.58 m, A_x = 7.22 m$

option A is correct

3 0

3 years ago

Two charges are in the configuration indicated here. The first charge, Q1 = –1.00 μC, sits at the origin. The second charge, Q2

blagie [28]

Answer:

$E_{net} = 3.6 \times 10^4 N/C$

Explanation:

As the two charges Q1 and Q2 are placed at some distance apart

so the electric field at mid point will be twice the electric field due to one charge

Because here the two charges are of opposite sign so here the electric field at mid point will be added due to both

so here we have

$E_{net} = 2E$

$E_{net} = 2(\frac{kQ}{r^2})$

distance of mid point from one charge is given as

$r = \frac{\sqrt{1^2 + 1^2}}{2}$

$E_{net} = 2 (\frac{(9\times 10^9)(1\times 10^{-6})}{(\frac{1}{\sqrt2})^2}$

$E_{net} = 3.6 \times 10^4 N/C$

5 0

3 years ago

Monochromatic light of wavelength 720 nm is incident on parallel slits, of width 0.420 mm, separated by 0.560 mm. A diffraction

ki77a [65]

Answer:

1.81×10^-4Io

Explanation:

Check attachment

4 0

4 years ago