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3 years ago

A roller coaster car with a mass of 17,690 kg is moving at a speed of 5 m/s over a hill that is 87.4 m above the

Physics

1 answer:

Sati [7]3 years ago

3 0

Answer:

$E=1.53\times 10^7\ J$

Explanation:

Given that,

The mass of the car, m = 17,690 kg

The speed of the car over the hill, v = 5 m/s

The car is 87.4 m above the ground.

We need to find the total mechanical energy of the car-Earth system. Mechanical energy is equal to the sum of kinetic energy and potential energy. So,

$E=mgh+\dfrac{1}{2}mv^2\\\\E=17690\times 9.8\times 87.4+\dfrac{1}{2}\times 17690 \times (5)^2\\\\E=1.53\times 10^7\ J$

So, the total mechanical energy of the car-Earth system is $1.53\times 10^7\ J$ .

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valkas [14]

Answer: m∠P ≈ 46,42°

because using the law of sines in ΔPQR

=> sin 75°/ 4 = sin P/3

so ur friend is wrong due to confusion between edges

+) we have: sin 75°/4 = sin P/3

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Explanation:

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3 years ago

Example of energy transfer from potential to kinetic and back

Alex_Xolod [135]

Swimmer and Divers. The Potential energy is transferred into Kinetic energy, and allows the diver to submerge into the water. The Kinetic energy then allows the diver to submerge and dive into the water. Potential energy however, is needed to allow the diver to get back out of the water after diving to get up and go and dive again, and then the Kinetic energy is transferred back to Potential energy to repeat the process.

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3 years ago

What voltage produces a current of 50 amps with a resistance of 20 ohms?<br>

PIT_PIT [208]

Answer:

1000 V

Explanation:

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3 years ago

When a slice of buttered toast is accidentally pushed over the edge of a counter, it rotates as it falls. If the distance to the

Masja [62]

Answer:

The smallest angular velocity is 4.42 rad/s and the largest angular velocity is 13.15 rad/s for the toast to hit and then topple to be butter-side down

Explanation:

62 cm = 0.62 m

Knowing that the vertical distance traveled is s = 0.62 m and gravitational acceleration is g = 9.81 m/s2, we can calculate the time of falling

$s = gt^2/2$

$0.62 = 9.81t^2/2$

$t^2 = 2*0.62/9.81 = 0.13$

$t = \sqrt{0.13} = 0.36 s$

If there's only 0.36s to rotate, and for the toast to hit and then topple to be butter-side down, then the angle of rotation must be between 90 and 270 degrees (Suppose that it starts with butter up and it rotates less than 1 revolution, or 360 degrees):

In other words (and units):

$\frac{\pi}{2} \leq \theta \leq \frac{3\pi}{2}$ rad

As $\omega = \theta / t$ :

$\frac{\pi}{2} / t \leq \theta / t \leq \frac{3\pi}{2} / t$ rad/s

$\frac{\pi}{2*0.36} \leq \omega \leq \frac{3\pi}{2*0.36}$ rad/s

$4.42 \leq \omega \leq 13.25$ rad/s

So the smallest angular velocity is 4.42 rad/s and the largest angular velocity is 13.15 rad/s for the toast to hit and then topple to be butter-side down

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3 years ago

If a person weighs 717 N on earth and 5320 N on the surface due to gravity on that planet? of a nearby planet, what is the accel

Studentka2010 [4]

The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.

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3 years ago

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