If a teacher had 48 red pens and the ratio of red to blue pens she owns is 6:1, she will have a total of 56 pens
Let the number of red pens be R and the number of blue pens be B.
R = 48
R / B = 6 / 1
48 / B = 6 / 1
B = 48 / 6
B = 8
Total number of pens = Number of red pens + Number of blue pens
Total number of pens = R + B
Total number of pens = 48 + 8
Total number of pens = 56 pens
Therefore, she has a total of 56 pens
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The elapsed time when the particle returns to the origin is determined from the ratio of initial velocity and acceleration of the particle.
<h3>Time of motion of the particle</h3>
The time of motion of the particle is calculated by applying Newton's second law of motion.
F = ma
F = m(v)/t
where;
- t is time of motion of the particle
- m is mass of the particle
- v is velocity of the particle
a = v - u/t
v = u + at
when the particle returns to the origin, direction of u, = negative.
final velocity = 0
0 = -u + at
at = u
t = u/a
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Liters
Grams
Degrees Celsius
The other answer choices are from the imperial system
Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN
Explanation: To find the answer we need to know more about the Newton's law of gravitation.
<h3>What is Newton's law of gravitation?</h3>
- Gravitation is the force of attraction between any two bodies.
- Every body in the universe attracts every other body with a force.
- This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between these two masses.
- Mathematically we can expressed it as,
<h3>How to solve the problem?</h3>
- Here, we have given with the data's,
- Thus, the force of attraction between these two bodies will be,
Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.
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Answer:
As beams of particles and their associated energy are given off, the pulsar will lose energy slowly, which will decrease the rate of its rotation. The frequency of pulses would therefore decrease, so that fewer pulses are observed in a given time span. The strength of the pulse signal will also decrease so the pulses will become fainter. Eventually, the pulsar should rotate so slowly and have such a low emission of radiation that it would no longer be observable.
